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Past Questions β€” 2025

Assistant & UDC β€’ 2025 β€’ Paper-II

Which feature in a word processor prevents words from being cut off at the edge of the page by moving them to the next line?

A) AutoFit
B) Word Wrap
C) Page Break
D) Alignment
Step-by-step reasoning: 1. Analysis of the requirement: The question asks for the feature that automatically moves a word to the next line when it reaches the right margin of the page to prevent it from being cut off. 2. Evaluating 'Word Wrap': Word Wrap is a standard feature in word processors (like MS Word) that automatically starts a new line when the current line is full, ensuring text stays within the printable area of the page without the user having to press 'Enter' manually. 3. Evaluating other options: - AutoFit: This is typically used in tables to adjust column width based on the content, not for general text flow on a page. - Page Break: This is a manual or automatic command that forces the text following it to start on a new page. - Alignment: This refers to the positioning of text relative to the margins (Left, Right, Center, or Justified), but it does not control the movement of words to the next line. 4. Conclusion: Word Wrap is the specific mechanism designed to handle the transition of text from one line to the next at the page edge.
Assistant & UDC β€’ 2025 β€’ Paper-II

Window is to pane as book is to:

A) Novel
B) Page
C) Cover
D) Shelf
This is a 'Whole-to-Part' analogy. To solve this, we must identify the relationship between the first pair of words and apply that same logic to the second pair. 1. Analyze the first pair: 'Window' is the whole object, and a 'pane' is a single, constituent part (a sheet of glass) that makes up the window. 2. Apply the logic to the second pair: We are looking for the constituent part that makes up a 'book'. Evaluating the options: - a. Novel: A novel is a type of book (Category/Example), not a part of a book. - b. Page: A page is a single, constituent part that makes up a book. This matches the 'Whole-to-Part' relationship (Window : Pane :: Book : Page). - c. Cover: While a cover is part of a book, it is the outer casing. A window is primarily composed of panes, just as a book is primarily composed of pages. - d. Shelf: A shelf is where a book is stored (Location), not a part of the book itself.
Assistant & UDC β€’ 2025 β€’ Paper-II

A spherical ball of diameter 21cm is melted and recast into cubes, each of side 1cm. Find the number of cubes so formed.

A) 2348
B) 5163
C) 1009
D) 4851
To find the number of cubes formed, we must divide the total volume of the spherical ball by the volume of a single cube. 1. **Calculate the volume of the spherical ball:** - Diameter (d) = 21 cm - Radius (r) = d / 2 = 21 / 2 = 10.5 cm - Formula for Volume of a Sphere = (4/3) * Ο€ * rΒ³ - Volume = (4/3) * (22/7) * (21/2) * (21/2) * (21/2) - Volume = (4/3) * (22/7) * (9261 / 8) - Volume = (4 * 22 * 9261) / (3 * 7 * 8) - Volume = 813048 / 168 = 4845.52... (Wait, let's simplify first) - Simplified: (4/3) * (22/7) * (21/2)Β³ = (4/3) * (22/7) * (21 * 21 * 21) / 8 - = (1/3) * (22/7) * (21 * 21 * 21) / 2 - = (22 * 21 * 21 * 21) / (3 * 7 * 2) - = (22 * 21 * 21 * 21) / 42 - = (22 * 21 * 21 * 21) / (2 * 21) - = (11 * 21 * 21) = 11 * 441 = 4851 cmΒ³ 2. **Calculate the volume of one cube:** - Side (a) = 1 cm - Formula for Volume of a Cube = aΒ³ - Volume = 1Β³ = 1 cmΒ³ 3. **Calculate the number of cubes:** - Number of cubes = Total Volume / Volume of one cube - Number of cubes = 4851 / 1 = 4851 Therefore, the number of cubes formed is 4851, which corresponds to option (d).
Assistant & UDC β€’ 2025 β€’ Paper-II

The price of a chair is Rs.500, It has been sold at two successive discount of 10% each. What is its selling price?

A) Rs.400
B) Rs.405
C) Rs.410
D) Rs.415
To find the selling price after two successive discounts, we apply the discounts sequentially to the remaining balance: 1. **Initial Price:** Rs. 500 2. **First Discount (10%):** Discount amount = 10% of 500 = (10/100) * 500 = Rs. 50 Price after first discount = 500 - 50 = Rs. 450 3. **Second Discount (10%):** The second discount is applied to the reduced price (Rs. 450), not the original price. Discount amount = 10% of 450 = (10/100) * 450 = Rs. 45 Final Selling Price = 450 - 45 = Rs. 405 **Alternative Method (Formula):** Selling Price = Marked Price Γ— (1 - d1/100) Γ— (1 - d2/100) Selling Price = 500 Γ— (1 - 10/100) Γ— (1 - 10/100) Selling Price = 500 Γ— 0.9 Γ— 0.9 Selling Price = 500 Γ— 0.81 = Rs. 405 **Analysis of Options:** - Option (a) Rs. 400 is incorrect because it assumes a flat 20% discount (500 - 100), ignoring that successive discounts are compounded. - Option (b) Rs. 405 is correct. - Options (c) and (d) are mathematically incorrect based on the given percentages.
Assistant & UDC β€’ 2025 β€’ Paper-II

Aldrin starts from his house to his office on motorcycle daily at a fixed time. If he covers this distance at 20 km/h, he is late by 8 minutes. However, if he covers this distance at 24 km/h, he arrives early by 5 minutes. The distance between his house and his office is:

A) 18 km
B) 20 km
C) 24 km
D) 26 km
To find the distance between Aldrin's house and his office, we can use the standard formula for distance when there is a difference in arrival times: $$\text{Distance} = \frac{S_1 \times S_2}{|S_1 - S_2|} \times \Delta T$$ Where: - $S_1 = 20$ km/h (first speed) - $S_2 = 24$ km/h (second speed) - $\Delta T$ is the total difference in time. Since he is late by 8 minutes in the first scenario and early by 5 minutes in the second, the total time difference is $8 + 5 = 13$ minutes. Converting this to hours, we get $\Delta T = \frac{13}{60}$ hours. Substituting these values into the formula: $$\text{Distance} = \frac{20 \times 24}{24 - 20} \times \frac{13}{60}$$ $$\text{Distance} = \frac{480}{4} \times \frac{13}{60}$$ $$\text{Distance} = 120 \times \frac{13}{60} = 2 \times 13 = 26\text{ km}$$ Thus, the correct distance is 26 km. **Why other options are incorrect:** - **Option a (18 km):** The time difference would be $(18/20 - 18/24) \times 60 = 9$ minutes, which does not match the required 13 minutes. - **Option b (20 km):** The time difference would be $(20/20 - 20/24) \times 60 = 10$ minutes, which is incorrect. - **Option c (24 km):** The time difference would be $(24/20 - 24/24) \times 60 = 12$ minutes, which is incorrect.
Assistant & UDC β€’ 2025 β€’ Paper-II

From the given choices, choose the pair that best represents a similar relationship to the word expressed in the original pair of words: AERIE : EAGLE

A) capital : government
B) buffalo : lion
C) unit : apartment
D) house : person
The relationship in the original pair is 'dwelling : inhabitant', as an aerie is the nest or dwelling place of an eagle. Option 'd' (house : person) perfectly mirrors this relationship, as a house is the dwelling place of a person. Option 'a' represents a seat of power rather than a physical dwelling. Option 'b' lists two different animals (prey and predator). Option 'c' represents a part-to-whole relationship.
Assistant & UDC β€’ 2025 β€’ Paper-II

The cost price of 18 articles is equal to the selling price of 15 articles. What is the profit/loss percent?

A) 13%
B) 15%
C) 18%
D) 20%
Step-by-step solution: 1. Let the Cost Price (CP) of one article be 'x'. 2. Therefore, the Cost Price of 18 articles = 18x. 3. According to the problem, the Selling Price (SP) of 15 articles is equal to the Cost Price of 18 articles. So, SP of 15 articles = 18x. 4. Now, find the Selling Price of one article: SP of 1 article = 18x / 15 = 1.2x. 5. Since the SP (1.2x) is greater than the CP (x), it is a profit. 6. Profit per article = SP - CP = 1.2x - x = 0.2x. 7. Profit Percentage = (Profit / CP) * 100 Profit Percentage = (0.2x / x) * 100 = 0.2 * 100 = 20%. Alternative Shortcut Method: Profit % = [(Difference in quantity) / (Quantity sold)] * 100 Profit % = [(18 - 15) / 15] * 100 Profit % = (3 / 15) * 100 = (1 / 5) * 100 = 20%.
Assistant & UDC β€’ 2025 β€’ Paper-II

A square park is surrounded by a path of uniform width 2m all around it. If the area of the park is 169m2 . Find the area of the path.

A) 56m2
B) 120m2
C) 192m2
D) 116m2
1. **Find the side of the square park**: Since the area of the square park is $169\text{ m}^2$, its side length is $\sqrt{169} = 13\text{ m}$. 2. **Find the side of the outer square (park + path)**: The path is $2\text{ m}$ wide all around, so we add $2\text{ m}$ to both sides of the park's length. Outer side = $13 + 2 + 2 = 17\text{ m}$. 3. **Calculate the total area**: Total area including the path = $17 \times 17 = 289\text{ m}^2$. 4. **Calculate the area of the path**: Area of the path = Total Area - Area of the park = $289 - 169 = 120\text{ m}^2$. * **Why other options are incorrect**: Options 'a' ($56\text{ m}^2$), 'c' ($192\text{ m}^2$), and 'd' ($116\text{ m}^2$) do not equal the correct difference between the outer and inner square areas ($289 - 169 = 120\text{ m}^2$).
Assistant & UDC β€’ 2025 β€’ Paper-II

The area of a square is twice the area of a circle. The area of a square is 2772 cmΒ². What is the length of the radius of a circle? (pi = 22/7)

A) 21 cm
B) 28 cm
C) 35 cm
D) 42 cm
Step-by-step solution: 1. **Identify given values**: - Area of the square ($A_{square}$) = $2772 \text{ cm}^2$. - Relationship: Area of the square is twice the area of the circle ($A_{square} = 2 \times A_{circle}$). - Value of $\pi = 22/7$. 2. **Find the area of the circle**: Since $A_{square} = 2 \times A_{circle}$, then $A_{circle} = A_{square} / 2$. $A_{circle} = 2772 / 2 = 1386 \text{ cm}^2$. 3. **Use the formula for the area of a circle to find the radius ($r$)**: The formula is $A_{circle} = \pi r^2$. $1386 = (22/7) \times r^2$ 4. **Solve for $r^2$**: $r^2 = (1386 \times 7) / 22$ $r^2 = 63 \times 7$ (since $1386 / 22 = 63$) $r^2 = 441$ 5. **Solve for $r$**: $r = \sqrt{441} = 21 \text{ cm}$. Comparing this result to the options: - Option (a) 21 cm matches our calculation. - Options (b), (c), and (d) are incorrect as their squares multiplied by $\pi$ do not equal 1386.
Assistant & UDC β€’ 2025 β€’ Paper-II

Suppose the first and the second letters of the English alphabet series switched places, also the third and the fourth, the fifth and the sixth and so on. In the new alphabet series thus formed, which letter would be the 20th letter from the left?

A) T
B) S
C) N
D) M
Step-by-step reasoning: 1. The standard English alphabet consists of 26 letters: A(1), B(2), C(3), D(4), E(5), F(6), G(7), H(8), I(9), J(10), K(11), L(12), M(13), N(14), O(15), P(16), Q(17), R(18), S(19), T(20), U(21), V(22), W(23), X(24), Y(25), Z(26). 2. The problem states that letters are switched in pairs: (1st and 2nd), (3rd and 4th), (5th and 6th), and so on. 3. This means for any even position 'n', the letter at that position in the new series is the letter that was at position 'n-1' in the original series. Conversely, for any odd position 'n', the letter is the one that was at position 'n+1' in the original series. 4. We are looking for the 20th letter from the left in the new series. 5. Since 20 is an even number, it forms a pair with the 19th letter (the 19th and 20th letters switched places). 6. Therefore, the letter at the 20th position in the new series is the letter that was originally at the 19th position. 7. The 19th letter of the standard English alphabet is 'S'. 8. Thus, the 20th letter in the modified series is S.
Assistant & UDC β€’ 2025 β€’ Paper-II

Ten years ago, Liana was four times as old as his son. Ten years hence, he will be twice the age of his son. Find the present ages of Liana and his son.

A) 55 & 25
B) 50 & 25
C) 50 & 20
D) 55 & 20
Let the present age of Liana be L and his son be S. 1. **Ten years ago:** Liana was four times as old as his son. L - 10 = 4(S - 10) L - 10 = 4S - 40 L - 4S = -30 --- (Equation 1) 2. **Ten years hence:** Liana will be twice as old as his son. L + 10 = 2(S + 10) L + 10 = 2S + 20 L - 2S = 10 --- (Equation 2) Subtracting Equation 1 from Equation 2: (L - 2S) - (L - 4S) = 10 - (-30) 2S = 40 S = 20 Substituting S = 20 in Equation 2: L - 2(20) = 10 L = 50 Thus, the present ages of Liana and his son are 50 and 20 respectively. **Why other options are incorrect:** - **Option a (55 & 25):** Ten years ago, their ages would be 45 and 15. 45 is not 4 times 15. - **Option b (50 & 25):** Ten years ago, their ages would be 40 and 15. 40 is not 4 times 15. - **Option d (55 & 20):** Ten years ago, their ages would be 45 and 10. 45 is not 4 times 10.
Assistant & UDC β€’ 2025 β€’ Paper-II

What option should fill the blank? SCD, TEF, UGH, ____, WKL

A) CMN
B) UJI
C) VIJ
D) IJT
To solve this alphabet series, we analyze the pattern of each letter position in the triplets: 1. First Letter: S β†’ T β†’ U β†’ ? β†’ W. The letters follow a consecutive alphabetical order. After U comes V. 2. Second Letter: C β†’ E β†’ G β†’ ? β†’ K. These letters skip one letter in between (C, [d], E, [f], G, [h], I, [j], K). Following this pattern, the next letter after G is I. 3. Third Letter: D β†’ F β†’ H β†’ ? β†’ L. These letters also skip one letter in between (D, [e], F, [g], H, [i], J, [k], L). Following this pattern, the next letter after H is J. Combining these results, the missing triplet is V + I + J = VIJ. Comparing with the options: - a. CMN: Incorrect (does not follow any of the patterns). - b. UJI: Incorrect (first letter should be V). - c. VIJ: Correct. - d. IJT: Incorrect (first letter should be V).
Assistant & UDC β€’ 2025 β€’ Paper-II

A and B can do a piece of work in 5 days. After completing 2/3 of work and then A left. The remaining work was done by B in 3 days. In how many day B alone can finish the work?

A) 9 days
B) 6 days
C) 5 days
D) 3 days
Step-by-step solution: 1. **Identify the total work and combined efficiency**: A and B together can complete the work in 5 days. Therefore, their combined efficiency (A + B) = 1/5 of the work per day. 2. **Analyze the work completed**: They worked together until 2/3 of the work was completed. Remaining work = 1 - 2/3 = 1/3 of the total work. 3. **Analyze B's solo work**: The problem states that B completed the remaining 1/3 of the work in 3 days. 4. **Calculate B's efficiency**: If B does 1/3 of the work in 3 days, then B's daily efficiency = (1/3) / 3 = 1/9 of the work per day. 5. **Determine the time for B to finish the whole work**: Time taken by B alone = Total Work / B's efficiency = 1 / (1/9) = 9 days. Verification of other options: - Option b (6 days): Incorrect. This would mean B does 1/6 of the work per day, meaning 1/3 of the work would take 2 days, not 3. - Option c (5 days): Incorrect. This is the combined time for A and B. - Option d (3 days): Incorrect. This is the time B took to finish only the remaining 1/3 of the work.
Assistant & UDC β€’ 2025 β€’ Paper-II

β€˜A’ is a place which is located 4 km away in the north-west direction from the capital β€˜M’. β€˜B’ is another place that is located 4 km away in the south-west direction from β€˜A’. β€˜ E’ is another place and that is located 4 km away in the north-west direction from β€˜B’. β€˜C’ is yet another place that is located 2 km away in the south-west direction from β€˜E’. In which direction is β€˜C’ located in relation to β€˜M’?

A) North
B) North-West
C) West
D) South-West
To solve this problem, we can use a coordinate system where the capital 'M' is the origin (0, 0). Let the unit of distance be 1 km. In a standard coordinate plane, North is +y, South is -y, East is +x, and West is -x. 1. **Position of A**: A is 4 km North-West of M. - North-West is a 45-degree angle between North and West. - x-coordinate of A = -4 * cos(45°) = -4 * (1/√2) = -2√2 - y-coordinate of A = 4 * sin(45°) = 4 * (1/√2) = 2√2 - A = (-2√2, 2√2) 2. **Position of B**: B is 4 km South-West of A. - South-West is a 45-degree angle between South and West. - x-coordinate of B = x_A - 4 * cos(45°) = -2√2 - 2√2 = -4√2 - y-coordinate of B = y_A - 4 * sin(45°) = 2√2 - 2√2 = 0 - B = (-4√2, 0) 3. **Position of E**: E is 4 km North-West of B. - x-coordinate of E = x_B - 4 * cos(45°) = -4√2 - 2√2 = -6√2 - y-coordinate of E = y_B + 4 * sin(45°) = 0 + 2√2 = 2√2 - E = (-6√2, 2√2) 4. **Position of C**: C is 2 km South-West of E. - x-coordinate of C = x_E - 2 * cos(45°) = -6√2 - (2 * 1/√2) = -6√2 - √2 = -7√2 - y-coordinate of C = y_E - 2 * sin(45°) = 2√2 - (2 * 1/√2) = 2√2 - √2 = √2 - C = (-7√2, √2) 5. **Direction of C relative to M**: - M is at (0, 0) and C is at (-7√2, √2). - Since the x-coordinate is negative and the y-coordinate is positive, C is in the North-West quadrant relative to M. Wait, let's re-evaluate the geometry simply: - M to A: NW (4km) - A to B: SW (4km). Since the distance is the same and the angle is 90 degrees, M-A-B forms a right-angled isosceles triangle. B is directly West of M. (Distance MB = 4 * sqrt(2)). - B to E: NW (4km). This is the same vector as M to A. So E is to the NW of B. - E to C: SW (2km). Let's look at the Y-axis (North/South) movements: - M -> A: + (4 * sin 45) - A -> B: - (4 * sin 45) [Net Y = 0] - B -> E: + (4 * sin 45) - E -> C: - (2 * sin 45) [Net Y = + (2 * sin 45)] Let's look at the X-axis (East/West) movements: - M -> A: - (4 * cos 45) - A -> B: - (4 * cos 45) - B -> E: - (4 * cos 45) - E -> C: - (2 * cos 45) - Net X = - (14 * cos 45) = -7√2 Since Net X is negative (West) and Net Y is positive (North), C is North-West of M. Correction: Re-reading the options and the path. - M(0,0) -> A(-2√2, 2√2) -> B(-4√2, 0) -> E(-6√2, 2√2) -> C(-7√2, √2). - C is at (-9.89, 1.41). This is clearly North-West of M. However, in many competitive exam patterns for this specific question, if the movement is viewed as a grid: - NW is (-1, 1), SW is (-1, -1). - M(0,0) -> A(-4, 4) -> B(-8, 0) -> E(-12, 4) -> C(-14, 2). - Result: North-West. Wait, let me re-read the prompt. If the options provided are North, North-West, West, South-West, and the calculation yields a positive Y and negative X, the answer is North-West. Let's double check the distance 'C' is 2km SW from 'E'. E is at (-6√2, 2√2). C is at (-6√2 - √2, 2√2 - √2) = (-7√2, √2). Since Y is still positive, it is North-West. Wait, if the question intended for C to be further south: If C was 4km SW from E, C would be at (-8√2, 0), which is West. But C is 2km SW from E. Let's re-verify the coordinates: - M: (0,0) - A: (-2.82, 2.82) - B: (-5.65, 0) - E: (-8.48, 2.82) - C: (-9.89, 1.41) C is North-West of M. Wait, looking at the options again. If the answer is 'West', the Y coordinate must be 0. For Y to be 0, the total North movement must equal total South movement. Norths: M->A (4), B->E (4). Total = 8 units of NW/NE. Souths: A->B (4), E->C (2). Total = 6 units of SW/SE. Net = 2 units North. Therefore, the position is North-West. Wait, let me check if I misread 'C is 2km away in the south-west direction from E'. No, it says 2km. If the distance from E to C was 4km, the answer would be West. Given the options and the standard nature of these problems, if the calculation results in North-West, option (b) is the correct one. Let's re-calculate one more time. - M to A: NW - A to B: SW - B to E: NW - E to C: SW Vector sum: (NW) + (SW) + (NW) + (SW_half) = 2(NW) + 1.5(SW) = 2(-1, 1) + 1.5(-1, -1) = (-2-1.5, 2-1.5) = (-3.5, 0.5). X is negative, Y is positive. This is North-West. Wait, I will re-read the question one more time. 'A' is 4km NW from 'M'. 'B' is 4km SW from 'A'. 'E' is 4km NW from 'B'. 'C' is 2km SW from 'E'. Direction of C from M: North components: 4(sin 45) - 4(sin 45) + 4(sin 45) - 2(sin 45) = 2(sin 45) = √2 (Positive) West components: 4(cos 45) + 4(cos 45) + 4(cos 45) + 2(cos 45) = 14(cos 45) = 7√2 (Positive West) Result: North-West. Wait, I see some versions of this problem online where the distance from E to C is 4km. If it were 4km, the answer would be West. With 2km, it is North-West. I will stick to the text provided. Correct Option: b. North-West
Assistant & UDC β€’ 2025 β€’ Paper-II

If nP3 = 504, find n.

A) 10
B) 6
C) 12
D) 9
The formula for permutations is given by nPr = n! / (n - r)!. Given: nP3 = 504 According to the formula: nP3 = n * (n - 1) * (n - 2) So, we need to find three consecutive integers whose product is 504. Step 1: Estimate the value of n. Since n * (n - 1) * (n - 2) β‰ˆ nΒ³, we can take the cube root of 504 to find an approximate value. 8Β³ = 512 9Β³ = 729 Since 504 is very close to 512, n should be around 8 or 9. Step 2: Test the options provided: - Option (a) n = 10: 10 * 9 * 8 = 720 (Too high) - Option (b) n = 6: 6 * 5 * 4 = 120 (Too low) - Option (c) n = 12: 12 * 11 * 10 = 1320 (Too high) - Option (d) n = 9: 9 * 8 * 7 = 504 (Correct) Verification: 9 * 8 = 72; 72 * 7 = 504. Therefore, n = 9.
Assistant & UDC β€’ 2025 β€’ Paper-II

The average weight of 24 students in a class is 35 kg. If the weight of the teacher is included, the average weight becomes 36 kg. Find the weight of the teacher.

A) 60 kg
B) 57 kg
C) 55 kg
D) 50 kg
To find the weight of the teacher, we can use two methods: the Total Weight method or the Deviation method. Method 1: Total Weight Method 1. Calculate the total weight of the 24 students: Total weight = Number of students Γ— Average weight = 24 Γ— 35 = 840 kg. 2. Calculate the total weight after the teacher is included: The number of people becomes 25 (24 students + 1 teacher), and the new average is 36 kg. Total weight = 25 Γ— 36 = 900 kg. 3. The weight of the teacher is the difference between the new total weight and the previous total weight: Teacher's weight = 900 kg - 840 kg = 60 kg. Method 2: Deviation Method (Shortcut) 1. The teacher's inclusion increased the average weight of all 25 people by 1 kg (from 35 kg to 36 kg). 2. This means the teacher brought enough weight to give 1 kg to each of the 24 students, plus their own new average weight. 3. Teacher's weight = New Average + (Previous Number of People Γ— Increase in Average) Teacher's weight = 36 + (24 Γ— 1) = 36 + 24 = 60 kg. Comparing this result to the options: - Option (a) 60 kg matches our calculation. - Options (b), (c), and (d) are incorrect as they do not satisfy the mathematical requirements of the average increase.
Assistant & UDC β€’ 2025 β€’ Paper-II

In how many ways can the letters of the words β€˜APPLE’ be arranged?

A) 30
B) 60
C) 90
D) 120
To find the number of ways to arrange the letters of the word 'APPLE', we use the formula for permutations of a multiset: n! / (p1! * p2! ... pk!), where 'n' is the total number of letters and 'p' represents the frequency of each repeating letter. 1. Count the total number of letters in 'APPLE': n = 5. 2. Identify repeating letters: The letter 'P' appears 2 times. 3. Apply the formula: Total arrangements = 5! / 2! 4. Calculate the factorials: 5! = 5 Γ— 4 Γ— 3 Γ— 2 Γ— 1 = 120; 2! = 2 Γ— 1 = 2. 5. Divide: 120 / 2 = 60. Therefore, there are 60 distinct ways to arrange the letters. Option (a) 30 is incorrect as it divides by 4; Option (c) 90 is mathematically unrelated; Option (d) 120 is incorrect because it fails to account for the duplicate 'P's.
Assistant & UDC β€’ 2025 β€’ Paper-II

Select the related number/letter/word from the given alternatives: Alleviate : Aggravate :: Elastic :?

A) Flexible
B) Rigid
C) Strong
D) Malleable
Step 1: Analyze the relationship between the first pair of words. 'Alleviate' means to make a problem or pain less severe, while 'Aggravate' means to make a problem or injury worse. These two words are antonyms (opposites). Step 2: Apply the same relationship to the second pair. The word 'Elastic' refers to a material or object that is flexible and can return to its original shape after being stretched or compressed. Step 3: Evaluate the options to find the antonym of 'Elastic': - (a) Flexible: This is a synonym of elastic. - (b) Rigid: This means stiff, unyielding, or unable to bend/stretch. This is the direct antonym of elastic. - (c) Strong: This refers to power or durability, not necessarily the ability to stretch or bend. - (d) Malleable: This refers to the ability to be hammered or pressed permanently out of shape, which is a different property from elasticity. Conclusion: Since the first pair consists of antonyms, the second pair must also consist of antonyms. Therefore, 'Rigid' is the correct opposite of 'Elastic'.
Assistant & UDC β€’ 2025 β€’ Paper-II

Mawia says, β€œIf you reverse the digits of my age, the number that you obtain will be Zova’s age. Zova is older than I am and the difference of my age and that of Zova’s will be one-eleventh of the sum of our ages.” The age of Mawia is:

A) 23 years
B) 34 years
C) 45 years
D) None of these
Let Mawia's age be represented as a two-digit number $10x + y$. Since Zova's age is the reverse of Mawia's and Zova is older, Zova's age is $10y + x$ (where $y > x$). 1. The difference between their ages is: $(10y + x) - (10x + y) = 9(y - x)$. 2. The sum of their ages is: $(10y + x) + (10x + y) = 11(x + y)$. 3. According to the problem, the difference is one-eleventh of the sum: $9(y - x) = \frac{1}{11} \times 11(x + y)$ $9y - 9x = x + y$ $8y = 10x \implies 4y = 5x$ Since $x$ and $y$ must be single-digit positive integers, the only possible solution is $x = 4$ and $y = 5$. Thus, Mawia's age is 45 years. - **Option a (23 years)** is incorrect: If Mawia is 23, Zova is 32. The difference is 9, but one-eleventh of their sum (55) is 5. - **Option b (34 years)** is incorrect: If Mawia is 34, Zova is 43. The difference is 9, but one-eleventh of their sum (77) is 7.
Assistant & UDC β€’ 2025 β€’ Paper-II

Lura is the only son of Liani who is the only daughter of Lawma. Sawmi is the mother of Lala and daughter-in-law of Liani. How is Lala related to Liani?

A) Son
B) Grandson
C) Husband
D) None of these
Let's break down the relationships step-by-step: 1. **Lura and Liani**: Lura is the only son of Liani. (Liani is the mother, Lura is the son). 2. **Liani and Lawma**: Liani is the only daughter of Lawma. (Lawma is the grandparent of Lura). 3. **Sawmi and Liani**: Sawmi is the daughter-in-law of Liani. Since Lura is Liani's only son, Sawmi must be married to Lura. 4. **Sawmi and Lala**: Sawmi is the mother of Lala. Since Sawmi is married to Lura, Lura is the father of Lala. 5. **Lala and Liani**: Liani is the mother of Lura, and Lura is the father of Lala. Therefore, Liani is the grandmother of Lala, and Lala is the grandchild of Liani. Regarding the options: - **a. Son**: Incorrect. Lura is the son of Liani. - **b. Grandson**: Correct. Lala is the child of Liani's son (Lura). While the gender of Lala is not explicitly stated, in the context of standard competitive exam multiple-choice questions, 'Grandson' is the only viable familial relationship provided that fits the generational gap. - **c. Husband**: Incorrect. Lura is the husband of Sawmi. - **d. None of these**: Incorrect, as 'Grandson' fits the relationship.
Assistant & UDC β€’ 2025 β€’ Paper-II

From the given choices, choose the pair that best represents a similar relationship to the word expressed in the original pair of words: DELTOID : MUSCLE

A) radius : bone
B) brain : nerve
C) tissue : organ
D) blood : vein
Step 1: Analyze the relationship in the original pair (DELTOID : MUSCLE). The deltoid is a specific type of muscle (specifically, the large triangular muscle covering the shoulder joint). Therefore, the relationship is 'Specific Example : General Category' or 'Type of'. Step 2: Evaluate the options based on this 'Type of' relationship: - Option (a) radius : bone: The radius is a specific bone in the forearm. This matches the 'Specific Example : General Category' relationship. - Option (b) brain : nerve: The brain is an organ composed of nerves, but it is not a 'type of' nerve. This is a 'Whole : Part' or 'Composition' relationship. - Option (c) tissue : organ: Tissues make up organs. This is a 'Part : Whole' relationship, and the order is reversed (General to Specific). - Option (d) blood : vein: Blood flows through veins. This is a 'Content : Container' relationship. Step 3: Conclusion. Only option (a) maintains the exact logical relationship established in the original pair.
Assistant & UDC β€’ 2025 β€’ Paper-II

Three numbers are in the ratio 3:2:5. If the sum of their squares is equal to 1862, find the smallest number.

A) 14
B) 21
C) 35
D) 7
Step-by-step solution: 1. Let the three numbers be represented as 3x, 2x, and 5x, based on the given ratio 3:2:5. 2. According to the problem, the sum of their squares is 1862. We can set up the equation: (3x)² + (2x)² + (5x)² = 1862 3. Calculate the squares: 9x² + 4x² + 25x² = 1862 4. Combine the like terms: 38x² = 1862 5. Solve for x²: x² = 1862 / 38 x² = 49 6. Solve for x: x = √49 = 7 7. The three numbers are: First number: 3 * 7 = 21 Second number: 2 * 7 = 14 Third number: 5 * 7 = 35 8. The smallest number among 21, 14, and 35 is 14. Verification of options: - Option (a) 14: Correct (the smallest number). - Option (b) 21: Incorrect (this is the middle number). - Option (c) 35: Incorrect (this is the largest number). - Option (d) 7: Incorrect (this is the common ratio multiplier 'x', not one of the numbers).
Assistant & UDC β€’ 2025 β€’ Paper-II

If A is the brother of B; B is the sister of C; and C is the father of D, how is D related to A?

A) Brother
B) Sister
C) Nephew
D) Cannot be established
Let's break down the relationships step-by-step: 1. A is the brother of B: This means A is male and B is his sibling. 2. B is the sister of C: This means B is female and C is her sibling. Therefore, A, B, and C are all siblings. 3. C is the father of D: This means C is male and D is the child of C. 4. Relationship between A and D: Since A is the brother of D's father (C), A is the paternal uncle of D. 5. Determining D's relation to A: The question asks how D is related to A. While we know A is the uncle, the gender of D is not specified in the problem. D could be the son of C (making D the nephew of A) or the daughter of C (making D the niece of A). Since the gender of D is unknown, we cannot definitively conclude if D is a nephew or a niece. Therefore, the relationship cannot be established from the given information.
Assistant & UDC β€’ 2025 β€’ Paper-II

In a school, 60% students play cricket. A student who does not play cricket, plays football. Every football player has got a two- wheeler. Which of the following conclusions cannot be drawn from the above data? i. 60% of the students do not have two- wheelers. ii. No cricketer has a two-wheeler. iii. Cricket players do not play football.

A) i and ii only
B) ii and iii only
C) i and iii only
D) i, ii and iii
Let's analyze the given statements logically: 1. '60% students play cricket' implies 40% do not play cricket. 2. 'A student who does not play cricket, plays football' means all non-cricketers are football players. Thus, 40% of students play football. 3. 'Every football player has got a two-wheeler' means all football players (the 40% non-cricketers) definitely have two-wheelers. Now let's evaluate the conclusions: - Conclusion (i): '60% of the students do not have two-wheelers.' This cannot be drawn. We know 40% (football players) definitely HAVE two-wheelers. We have no information about whether the 60% (cricketers) have two-wheelers or not. They might, or they might not. - Conclusion (ii): 'No cricketer has a two-wheeler.' This cannot be drawn. The premises state that football players have two-wheelers, but they do not state that ONLY football players have them. Cricketers could also own two-wheelers. - Conclusion (iii): 'Cricket players do not play football.' This cannot be drawn. The premise says 'those who do NOT play cricket play football'. It does not say that those who DO play cricket cannot also play football. There could be an overlap where some students play both. Since none of the three conclusions can be logically deduced from the given data, the correct option is (d) i, ii and iii.
Assistant & UDC β€’ 2025 β€’ Paper-II

In Excel, which of the following is not a valid chart type?

A) Line Chart
B) Pie Chart
C) Cylinder Chart
D) Flowchart
In Microsoft Excel, a 'Chart' is a visual representation of numeric data. 1. **Line Chart (Option a):** A standard chart type used to show trends over time. 2. **Pie Chart (Option b):** A standard chart type used to show proportions of a whole. 3. **Cylinder Chart (Option c):** A variation of the 3D Column chart where the bars are rendered as cylinders. It is a valid built-in chart style in Excel. 4. **Flowchart (Option d):** A flowchart is a diagram that represents a process or workflow. While you can create a flowchart in Excel using 'Shapes' or 'SmartArt', it is not a 'Chart Type' (which requires a data range to be plotted). Flowcharts are diagrams, not data-driven charts. Therefore, Flowchart is not a valid chart type in the Excel Chart menu.