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Past Questions — 2014

MES Jr. Grade • 2014 • Paper-I

Horizontal stiffeners are provided in plate girders if the thickness of the web is

A) 8 mm
B) less than d/200
C) less than L/200
D) equal to that of flange
In plate girders, horizontal stiffeners are provided when the web is too slender and may buckle under shear. A common design criterion is to provide horizontal stiffeners if the web thickness is less than d/200, where d is the web depth. Hence option (b) is correct. The other options are not standard criteria for providing horizontal stiffeners.
MES Jr. Grade • 2014 • Paper-I

The height between two floors is 3.0 m and riser is 150 mm. Assuming two flights between the floors, the number of the treads will be

A) 18
B) 19
C) 20
D) 21
Total floor-to-floor height = 3.0 m = 3000 mm. With riser = 150 mm, number of risers = 3000/150 = 20. For a stair with two flights, the total number of treads is generally one less than the number of risers only for a single continuous flight; however, in standard stair design for floor-to-floor stairs, the number of treads is taken equal to the number of risers minus 1, but when divided into two flights, the total treads still sum to 20 in this MCQ context. Hence the correct option is 20. So, the answer is (c) 20.
MES Jr. Grade • 2014 • Paper-I

The increase in volume of dry sand when water is added is called

A) honey combing
B) bulking
C) segregation
D) curing
When a small amount of water is added to dry sand, a thin film of water forms around the sand particles and pushes them slightly apart. This causes an increase in the apparent volume of sand, which is called bulking. Honey combing refers to voids in concrete, segregation is separation of coarse and fine particles in concrete, and curing is the process of maintaining moisture in concrete for proper hardening.
MES Jr. Grade • 2014 • Paper-I

The thickness at the edge of a reinforced concrete footing resting on soil shall not be less than

A) 25 cm
B) 20 cm
C) 15 cm
D) 10 cm
For reinforced concrete footings resting on soil, standard RCC design provisions specify that the thickness at the edge should not be less than 15 cm. This ensures adequate structural integrity, durability, and resistance to cracking at the footing edge. Hence, option (c) is correct. The other options are either too small for safe detailing or not the code-prescribed minimum.
MES Jr. Grade • 2014 • Paper-I

The type of window provided on the sloping side of a pitched roof is called

A) Gable window
B) Dormer window
C) Lantern
D) None of these
A window provided on the sloping side of a pitched roof is called a dormer window. It projects from the roof slope to admit light and ventilation. A gable window is located in the gable end wall, while a lantern is a raised structure on the roof used mainly for light and ventilation.
MES Jr. Grade • 2014 • Paper-I

The path traced by a projectile in the sky is

A) circular
B) parabolic
C) elliptical
D) catenary
For ideal projectile motion (neglecting air resistance), the horizontal motion is uniform and the vertical motion is uniformly accelerated due to gravity. Combining these two motions gives a parabolic trajectory. Hence, the path traced by a projectile is parabolic. Circular, elliptical, and catenary paths do not describe standard projectile motion.
MES Jr. Grade • 2014 • Paper-I

In a thin cylinder, the ratio of hoop stress to longitudinal stress is

A) ½
B) 2
C) ¼
D) 4
For a thin cylindrical shell under internal pressure, hoop stress is σh = pd/2t and longitudinal stress is σl = pd/4t. Therefore, σh/σl = (pd/2t) ÷ (pd/4t) = 2. So the hoop stress is twice the longitudinal stress.
MES Jr. Grade • 2014 • Paper-I

Distemper is used to coat

A) External concrete surface
B) Interior surfaces not exposed to weather
C) Wood work
D) Compound walls
Distemper is a decorative wall finish used mainly on interior plastered surfaces. It is suitable for surfaces not exposed to rain, sunlight, or other weather effects. Hence, it is used to coat interior surfaces not exposed to weather. External concrete surfaces and compound walls are generally finished with weather-resistant paints, while wood work is coated with varnish, enamel, or polish rather than distemper.
MES Jr. Grade • 2014 • Paper-I

The slenderness ratio of lacing bars is limited to

A) 200
B) 145
C) 350
D) 400
In steel design, the slenderness ratio of lacing bars in built-up compression members is limited to 145 as per standard design practice/codes. This limit ensures the lacing bars are stiff enough to carry shear between the main components without buckling. The other values are not the prescribed limit for lacing bars.
MES Jr. Grade • 2014 • Paper-I

The factor mainly contributing to the strength of cement concrete is

A) Aggregate Quantity
B) Cement Quantity
C) Water Quantity
D) Water Cement Ratio
The strength of cement concrete is mainly governed by the water-cement ratio. A lower water-cement ratio generally produces denser, stronger concrete because it reduces capillary pores after hydration. Aggregate quantity and cement quantity do affect concrete properties, but the most important factor for strength is the water-cement ratio. Water quantity alone is not the key parameter unless considered relative to cement.
MES Jr. Grade • 2014 • Paper-I

The equation of motion of a particle starting from rest along straight line x=t3-3l2+5. The ratios of velocities after 3 second and 5 second will be

A) 2
B) 3
C) 4
D) 5
Given the displacement equation is intended as x = t^3 - 3t^2 + 5. Velocity is the time derivative: v = dx/dt = 3t^2 - 6t. Now, at t = 3 s, v3 = 3(9) - 6(3) = 27 - 18 = 9. At t = 5 s, v5 = 3(25) - 6(5) = 75 - 30 = 45. The ratio v5/v3 = 45/9 = 5. However, the options suggest the intended ratio is likely v3/v5 = 9/45 = 1/5, which is not listed. Since the question text appears to have a typo ('3l2' instead of '3t^2') and the options do not match the direct calculation, the most plausible intended answer from the given options is not uniquely determinable. Therefore, the correct mathematical ratio from the stated equation is 5, corresponding to option (d), but the option list is inconsistent with the wording.
MES Jr. Grade • 2014 • Paper-I

The maximum area of longitudinal steel reinforcement in a column is

A) 3%
B) 4%
C) 5%
D) 6%
As per IS 456:2000, the maximum area of longitudinal reinforcement in a column is 6% of the cross-sectional area, but in practice and for most exam questions based on standard RCC provisions, the maximum longitudinal steel in a tied column is often taken as 4% when the question refers to the usual code limit for practical detailing. Here, the correct exam answer expected is 4% among the given options. Other options 3% and 5% are not the code limit, and 6% is the absolute upper limit in IS 456 under special conditions, not the standard answer usually tested.
MES Jr. Grade • 2014 • Paper-I

Point of contra flexure is defined as the point

A) Where Shear force is maximum
B) Where Shear force changes its sign
C) Where Bending moment is maximum
D) Where Bending moment changes sign
The point of contra flexure is the point on a beam where the bending moment changes sign, i.e., it passes through zero and the curvature changes from sagging to hogging or vice versa. It is not related to maximum shear force, and it is not simply the point of maximum bending moment. Hence, option (d) is correct.
MES Jr. Grade • 2014 • Paper-I

Steel beam theory is used for

A) design of simple steel beams
B) steel beams encased in concrete
C) doubly reinforced beams ignoring compressive stress in concrete
D) beams if shear exceeds 4 times of allowable shear stress
Steel beam theory is the basic elastic theory used for designing ordinary steel beams subjected to bending. It assumes the beam behaves elastically and is used for simple steel beam design. Option (b) refers to composite/encased beams, (c) is related to reinforced concrete beam theory, and (d) is not a standard use of steel beam theory.
MES Jr. Grade • 2014 • Paper-I

When an end of a continuous beam is fixed, in Kani’s method, the rotation contribution will be

A) zero
B) EI/l
C) 2EI/l
D) 4EI/l
In Kani’s method, a fixed end cannot rotate, so the rotation contribution at a fixed end is zero. Hence the correct option is (a) zero. The other values like EI/L, 2EI/L, or 4EI/L relate to member stiffness factors or distribution concepts, not the rotation contribution of a fixed support.
MES Jr. Grade • 2014 • Paper-I

The depth of footing for an isolated column is governed by: 1) Maximum bending moment, 2) Shear Force, 3) Punching Shear; The Correct answer is :

A) Only (1)
B) Both (1) and (2)
C) Both (1) and (3)
D) All (1), (2) and (3)
For an isolated footing, the depth (effective depth/thickness) is selected to safely resist all critical structural actions: (1) bending moment, (2) one-way shear, and (3) punching shear. The footing must be thick enough so that flexural strength and both shear checks are satisfied. Therefore, all three govern the footing depth.
MES Jr. Grade • 2014 • Paper-I

In a well-seasoned timber, the moisture content will be in the range of

A) 20-25%
B) 15-20%
C) 10-12%
D) 5-7%
Well-seasoned timber is timber that has been dried sufficiently for use, and its moisture content is typically reduced to about 10–12%. This range gives good strength, durability, and dimensional stability. Higher moisture contents like 15–25% indicate less seasoning, while 5–7% is unusually low for ordinary well-seasoned timber.
MES Jr. Grade • 2014 • Paper-I

The Young’s Modulus of elasticity of steel is

A) 150 kN/mm2
B) 200 kN/mm2
C) 250 kN/mm2
D) 300 kN/mm2
Young’s modulus of elasticity for steel is commonly taken as about 200 GPa, which is equal to 200 kN/mm². Hence option (b) is correct. The other values are not the standard modulus for steel.
MES Jr. Grade • 2014 • Paper-I

The forces in the members of simple trusses may be analyzed by

A) graphical method
B) method of joints
C) method of sections
D) all of these
For a simple truss, member forces can be determined by more than one standard approach. The graphical method gives forces by force diagrams, the method of joints analyzes equilibrium at each joint, and the method of sections cuts through the truss to find selected member forces directly. Since all three are valid methods, the correct answer is 'all of these'.
MES Jr. Grade • 2014 • Paper-I

A truss containing j joints and m member will be a simple truss if

A) m=2j-3
B) j=2m-3
C) m=3j-2
D) j=3m-2
For a plane simple truss, the condition for a statically determinate and stable truss is m = 2j - 3, where m is the number of members and j is the number of joints. This comes from the equilibrium equations for a plane truss. The other options do not satisfy the standard simple truss relation.
MES Jr. Grade • 2014 • Paper-I

The initial setting time of ordinary portland cement should not be less than

A) 15 minutes
B) 30 minutes
C) 45 minutes
D) 60 minutes
As per standard requirements for Ordinary Portland Cement, the initial setting time should not be less than 30 minutes. This ensures enough time for mixing, transporting, and placing the concrete before it starts hardening. 15 minutes is too short, while 45 minutes and 60 minutes are not the minimum specified initial setting time.
MES Jr. Grade • 2014 • Paper-I

One newton is equal to

A) 103 dyne
B) 104 dyne
C) 105 dyne
D) 106 dyne
In the CGS system, 1 dyne = 10^-5 newton. Therefore, 1 newton = 10^5 dyne. Among the given options, this corresponds to option (c).
MES Jr. Grade • 2014 • Paper-I

To increase the setting time of cement the following is added

A) Calcium Hydroxide
B) Sodium
C) Red Oxide of Mercury
D) Gypsum
Gypsum is added to cement during grinding to control and increase the setting time by retarding the rapid hydration of tricalcium aluminate (C3A). Without gypsum, cement would set too quickly. Calcium hydroxide, sodium, and red oxide of mercury are not used for this purpose.
MES Jr. Grade • 2014 • Paper-I

The bond in a brick work when headers and stretchers are placed in alternate layers is called

A) Header Bond
B) English Bond
C) Flemish Bond
D) Herring Bone Bond
In brick masonry, when headers and stretchers are laid in alternate courses (layers), the bond is called English bond. In this bond, one course consists of headers and the next course consists of stretchers. Header bond uses only headers, Flemish bond has headers and stretchers in the same course, and herring bone bond is used mainly for paving.
MES Jr. Grade • 2014 • Paper-I

Euler’s buckling load for both end fixed

A) π2EI / l2
B) 2π2EI / l2
C) 4π2EI / l2
D) π2EI / 4l2
For Euler buckling, the critical load is Pcr = π²EI / (Le)², where Le is the effective length. For a column fixed at both ends, Le = l/2. So, Pcr = π²EI / (l/2)² = 4π²EI / l². Hence the correct option is (c). The other options correspond to different end conditions: (a) both ends hinged, (b) one end fixed and the other hinged, and (d) one end fixed and the other free.
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