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MES Jr. Grade • 2024 • Paper-II

A Zener diode is operating in the breakdown region. The voltage across it will:

A) Increase rapidly with current
B) Decrease rapidly with current
C) Remain almost constant with current
D) Vary sinusoidally
A Zener diode is a specially designed PN junction diode that is intended to operate in the reverse breakdown region. When the reverse bias voltage reaches the Zener breakdown voltage (Vz), the diode enters the breakdown region. In this region, the I-V characteristic curve becomes nearly vertical. This means that even if the current flowing through the diode (Iz) increases significantly, the voltage across the diode (Vz) remains almost constant. This unique property is why Zener diodes are widely used as voltage regulators to provide a stable reference voltage despite fluctuations in load current or input voltage. Analysis of other options: - Option (a) is incorrect because a rapid increase in voltage with current would describe a standard resistor or a diode in the forward region, not a Zener in breakdown. - Option (b) is incorrect as the voltage does not decrease when current increases in the breakdown region. - Option (d) is incorrect because sinusoidal variation is a characteristic of an AC signal source, not the intrinsic V-I characteristic of a diode component.
MES Jr. Grade • 2024 • Paper-II

What is meant by polarization of the wave? Explain the different types of wave polarization.

MES Jr. Grade • 2024 • Paper-II

Routh Hurwitz criterion gives:

A) Number of roots in the right half of the s-plane
B) Value of the roots
C) Number of roots in the left half of the s-plane
D) Number of roots in the top half of the s-plane
The Routh-Hurwitz stability criterion is a mathematical method used in control systems to determine the stability of a linear time-invariant (LTI) system by examining the characteristic equation. 1. **Purpose**: The primary goal of the Routh-Hurwitz criterion is to determine if any roots of the characteristic equation lie in the Right Half of the s-plane (RHP). If any root exists in the RHP, the system is unstable. 2. **Mechanism**: By constructing a Routh array from the coefficients of the characteristic polynomial, the criterion states that the number of sign changes in the first column of the Routh array is equal to the number of roots of the characteristic equation located in the right half of the s-plane. 3. **Analysis of Options**: - **Option (a)**: Correct. The number of sign changes in the first column directly indicates the number of roots in the RHP. - **Option (b)**: Incorrect. Routh-Hurwitz tells us *how many* roots are in the RHP, but it does not provide the *exact numerical values* of those roots. Finding the values would require solving the polynomial (e.g., using root-finding algorithms). - **Option (c)**: Incorrect. While you can infer the number of roots in the left half by subtracting the RHP roots from the total degree of the polynomial, the criterion's direct output is the count of RHP roots. - **Option (d)**: Incorrect. The s-plane is divided into left and right halves for stability analysis; the 'top half' (imaginary axis) does not determine stability in the context of the Routh-Hurwitz criterion.
MES Jr. Grade • 2024 • Paper-II

What is transistor biasing? What are the requirements of a good biasing circuit?

MES Jr. Grade • 2024 • Paper-II

Which code changes only one bit between successive numbers?

A) BCD
B) Gray code
C) Excess-3
D) ASCII
The question asks for a code where only one bit changes between successive numbers. This is the defining characteristic of a 'unit-distance code'. 1. **Gray Code (Correct):** Also known as reflected binary code, it is specifically designed so that two successive values differ by only one bit. This property is crucial in digital systems to prevent 'glitches' or spurious outputs during transitions in hardware like rotary encoders or asynchronous FIFO pointers. 2. **BCD (Binary Coded Decimal):** This is a weighted code where each decimal digit is represented by 4 bits. For example, moving from 1 (0001) to 2 (0010) involves two bit changes (the last bit changes from 1 to 0, and the second-to-last changes from 0 to 1). 3. **Excess-3:** This is a non-weighted code derived by adding 3 to the BCD value. Like BCD, it does not maintain a unit-distance property. For example, 0 (0011) to 1 (0100) involves three bit changes. 4. **ASCII (American Standard Code for Information Interchange):** This is a character encoding standard for text, not a numerical sequence designed for unit-distance transitions.
MES Jr. Grade • 2024 • Paper-II

Discuss the effect of feedback on noise and distortion in control systems.

MES Jr. Grade • 2024 • Paper-II

Explain the difference between waveguide modes TE, TM, and TEM with examples of where each occurs.

MES Jr. Grade • 2024 • Paper-II

An isolator allows microwave power to pass:

A) In both directions
B) In one direction only
C) With attenuation in both directions
D) With amplification in one direction
A microwave isolator is a non-reciprocal two-port device. Its primary function is to allow microwave power to flow in one direction (from the input port to the output port) with minimal attenuation, while absorbing or blocking power flowing in the opposite direction (from the output port back to the input port). This is typically achieved using ferrite materials and the principle of Faraday rotation. - Option (a) is incorrect because a device that allows power in both directions is called a reciprocal device (like a cable or a standard attenuator). - Option (c) is incorrect because while there is some insertion loss in the forward direction, the device is specifically designed to provide high attenuation in only one direction, not both. - Option (d) is incorrect because an isolator is a passive device; it cannot provide amplification.
MES Jr. Grade • 2024 • Paper-II

Find the force between 2 C and -1 C separated by a distance 1m in air (in newton).

A) 18 X 106
B) 18 X 109
C) 18 X 10-6
D) 18 X 108
To find the force between two point charges, we use Coulomb's Law: F = k * (|q1 * q2|) / r², where: - k is the electrostatic constant (approximately 8.987 × 10⁹ N·m²/C², often rounded to 9 × 10⁹ N·m²/C² for competitive exams). - q1 = 2 C - q2 = -1 C - r = 1 m Step-by-step calculation: 1. Calculate the product of the magnitudes of the charges: |2 C * (-1 C)| = 2 C². 2. Square the distance: (1 m)² = 1 m². 3. Apply the formula: F = (9 × 10⁹ N·m²/C²) * (2 C²) / (1 m²). 4. F = 18 × 10⁹ N. Since the charges have opposite signs, the force is attractive. The magnitude is 18 × 10⁹ Newtons. Comparing this to the options: - Option (a) 18 X 10⁶ is incorrect (wrong power of 10). - Option (b) 18 X 10⁹ matches our calculation. - Option (c) 18 X 10⁻⁶ is incorrect (wrong power of 10). - Option (d) 18 X 10⁸ is incorrect (wrong power of 10).
MES Jr. Grade • 2024 • Paper-II

The S-matrix element S21 represents:

A) Reflection coefficient at port 1
B) Transmission from port 1 to port 2
C) Transmission from port 2 to port 1
D) Isolation between ports
In Microwave Engineering, the Scattering Matrix (S-matrix) is used to describe the electrical behavior of multi-port networks. The elements of the S-matrix are denoted as Sij, where 'i' represents the port where the wave is observed (output) and 'j' represents the port where the wave is incident (input). 1. S11: The wave is incident at port 1 and observed at port 1. This represents the reflection coefficient at port 1. 2. S21: The wave is incident at port 1 and observed at port 2. This represents the forward transmission coefficient from port 1 to port 2. 3. S12: The wave is incident at port 2 and observed at port 1. This represents the reverse transmission coefficient from port 2 to port 1. 4. S22: The wave is incident at port 2 and observed at port 2. This represents the reflection coefficient at port 2. Therefore, S21 specifically describes the transmission from port 1 to port 2. Option (a) refers to S11, option (c) refers to S12, and option (d) refers to the general concept of isolation (which is achieved when S21 and S12 are very small).
MES Jr. Grade • 2024 • Paper-II

In a synchronous counter:

A) All flip-flops are clocked together
B) Flip-flops are clocked in sequence
C) No clock is required
D) It cannot count in reverse
In digital electronics, counters are classified into two main types based on how they are clocked: 1. **Synchronous Counters**: In these counters, the clock input of every flip-flop is connected to a common clock signal. This means all flip-flops trigger simultaneously (at the same time), ensuring that all state transitions occur synchronously. This eliminates the 'ripple' effect and allows for higher operating frequencies. 2. **Asynchronous (Ripple) Counters**: In these counters, the clock is applied only to the first flip-flop. The output of the first flip-flop then serves as the clock for the second, and so on. This creates a sequential delay (ripple) as the signal propagates through the chain. Evaluating the options: - **Option a** is correct because it describes the fundamental definition of a synchronous counter. - **Option b** describes an asynchronous or ripple counter. - **Option c** is incorrect because all counters require a clock signal to trigger state changes. - **Option d** is incorrect because synchronous counters can be designed to count both up and down (Up/Down Counter).
MES Jr. Grade • 2024 • Paper-II

The stability of a control system can be determined from:

A) Root locus
B) Nyquist plot
C) Bode plot
D) All of the above
Stability analysis is a fundamental part of control systems engineering, and it can be performed using both time-domain and frequency-domain methods. 1. Root Locus (Option a): This is a graphical method that shows how the poles of the closed-loop transfer function move in the s-plane as a system parameter (usually the gain K) varies. If any part of the root locus enters the right-half of the s-plane, the system becomes unstable. Thus, it is used to determine absolute and relative stability. 2. Nyquist Plot (Option b): Based on the Nyquist Stability Criterion, this frequency-domain method uses the open-loop frequency response to determine the stability of the closed-loop system by observing the encirclements of the critical point (-1, j0). It is a powerful tool for determining absolute stability. 3. Bode Plot (Option c): This method represents the frequency response in terms of magnitude and phase. Stability is determined using the Gain Margin (GM) and Phase Margin (PM). If both GM and PM are positive, the system is stable. Since all three methods are valid and widely used tools for determining the stability of a control system, the correct answer is 'All of the above'.
MES Jr. Grade • 2024 • Paper-II

In a differential amplifier, the common-mode gain should be:

A) High
B) Low
C) Equal to differential gain
D) Zero
A differential amplifier is designed to amplify the difference between two input signals (differential mode) while rejecting signals that are common to both inputs (common-mode), such as noise or interference. 1. **Differential Gain (Ad):** This is the gain applied to the difference between the two inputs. For a useful amplifier, this should be high. 2. **Common-Mode Gain (Ac):** This is the gain applied to signals that appear identically on both inputs. In an ideal scenario, the amplifier should completely ignore these signals. 3. **Common-Mode Rejection Ratio (CMRR):** This is defined as the ratio of differential gain to common-mode gain (CMRR = Ad / Ac). To maximize the CMRR (which indicates a better quality amplifier), the common-mode gain (Ac) must be as small as possible. Therefore, for optimal performance and noise rejection, the common-mode gain should be low. While 'Zero' (option d) is the ideal theoretical value, in practical engineering and circuit design, the goal is to keep it 'Low'. In the context of standard multiple-choice questions for electronics, 'Low' is the correct descriptive requirement for a functional differential amplifier.
MES Jr. Grade • 2024 • Paper-II

The root locus of a system starts at:

A) Zeros and ends at poles
B) Poles and ends at zeros
C) Origin and ends at infinity
D) None of the above
In control systems, the Root Locus is a graphical representation of the paths (loci) of the closed-loop poles as a system parameter (usually the gain 'K') is varied from 0 to infinity. 1. **Starting Point (K = 0):** The characteristic equation of a closed-loop system is given by 1 + KG(s)H(s) = 0. When K = 0, the equation reduces to the open-loop characteristic equation. Therefore, the root locus starts at the open-loop poles. 2. **Ending Point (K → ∞):** As K approaches infinity, the closed-loop poles move toward the open-loop zeros of the system. If there are more poles than zeros, the remaining branches move toward infinity along specific asymptotes. Comparing this to the options: - Option (a) is the reverse of the actual behavior. - Option (b) correctly states that the locus starts at poles and ends at zeros. - Option (c) is incorrect as the origin is not the universal starting point.
MES Jr. Grade • 2024 • Paper-II

Find the standing wave ratio, when a load impedance of 250Ω is connected to a 75Ω line.

A) 0.3
B) 75
C) 250
D) 3.33
To find the Standing Wave Ratio (SWR), we follow these steps: 1. **Identify Given Values**: - Characteristic Impedance of the line ($Z_0$) = $75\Omega$ - Load Impedance ($Z_L$) = $250\Omega$ 2. **Calculate the Reflection Coefficient ($\Gamma$)**: The reflection coefficient is given by the formula: $$\Gamma = \frac{Z_L - Z_0}{Z_L + Z_0}$$ $$\Gamma = \frac{250 - 75}{250 + 75} = \frac{175}{325} \approx 0.5385$$ 3. **Calculate the Standing Wave Ratio (SWR)**: The SWR is related to the reflection coefficient by the formula: $$SWR = \frac{1 + |\Gamma|}{1 - |\Gamma|}$$ Alternatively, for purely resistive loads, SWR can be calculated directly as the ratio of the larger impedance to the smaller impedance: $$SWR = \frac{Z_L}{Z_0} \text{ (if } Z_L > Z_0\text{)}$$ $$SWR = \frac{250}{75} = 3.333...$$ 4. **Conclusion**: The calculated SWR is approximately 3.33. - Option (a) 0.3 is incorrect as SWR must always be $\ge 1$. - Option (b) 75 and (c) 250 are simply the given impedance values and do not represent the ratio. - Option (d) 3.33 matches our calculation.
MES Jr. Grade • 2024 • Paper-II

The dominant mode in a circular waveguide is:

A) TE 11
B) TM 01
C) TE 01
D) TM 11
In waveguide theory, the 'dominant mode' is defined as the mode with the lowest cutoff frequency. For a circular waveguide of radius 'a', the cutoff frequency for any mode is given by the formula: fc = (chi_mn / 2πa) * c, where chi_mn is the root of the Bessel function (for TM modes) or the root of the derivative of the Bessel function (for TE modes). 1. For TE modes, the smallest root is chi'_11 ≈ 1.841 (for TE11). 2. For TM modes, the smallest root is chi_01 ≈ 2.405 (for TM01). 3. The TE01 mode has a root chi'_01 ≈ 3.832. Comparing these values, the TE11 mode has the smallest root (1.841), which results in the lowest cutoff frequency. Therefore, TE11 is the dominant mode in a circular waveguide. - Option b (TM 01) is the dominant TM mode, but its cutoff frequency is higher than TE 11. - Option c (TE 01) has a significantly higher cutoff frequency than TE 11. - Option d (TM 11) has a higher cutoff frequency than both TE 11 and TM 01.
MES Jr. Grade • 2024 • Paper-II

The efficiency of a class-C power amplifier is typically:

A) 25–50%
B) 50–70%
C) 70–85%
D) >85%
Power amplifiers are classified based on their conduction angle (the portion of the input cycle for which the transistor conducts). 1. **Class A:** Conducts for the full 360° of the cycle. It has the highest linearity but the lowest efficiency (maximum theoretical efficiency is 25% for series-fed and 50% for transformer-coupled). 2. **Class B:** Conducts for 180° of the cycle. It is more efficient than Class A, with a maximum theoretical efficiency of 78.5%. 3. **Class AB:** Conducts for slightly more than 180° to reduce crossover distortion. Its efficiency falls between Class A and Class B. 4. **Class C:** Conducts for less than 180° (typically much less). Because the transistor is 'off' for a large portion of the cycle, it draws very little average current from the power supply compared to the output power delivered to the load (which is usually a tuned LC circuit). This results in very high efficiency, typically ranging from 80% to 90% or even higher, often exceeding 85% in practical high-frequency applications. Therefore, among the given options, '>85%' is the most accurate description of Class C amplifier efficiency.
MES Jr. Grade • 2024 • Paper-II

How is a J-K flip-flop made to toggle?

A) J = 0, K = 0
B) J = 1, K = 0
C) J = 0, K = 1
D) J = 1, K = 1
A J-K flip-flop is a universal flip-flop that overcomes the 'invalid state' problem of the S-R flip-flop. Its behavior is determined by the inputs J and K as follows: 1. **Hold State (J=0, K=0):** The output remains unchanged (Q_next = Q_present). This corresponds to option (a). 2. **Reset State (J=0, K=1):** The output is forced to 0 (Q_next = 0). This corresponds to option (c). 3. **Set State (J=1, K=0):** The output is forced to 1 (Q_next = 1). This corresponds to option (b). 4. **Toggle State (J=1, K=1):** The output switches to the complement of its current state (Q_next = NOT Q_present). If the output was 0, it becomes 1; if it was 1, it becomes 0. This is known as the 'toggle' condition. Therefore, to make a J-K flip-flop toggle, both inputs J and K must be set to high (1).
MES Jr. Grade • 2024 • Paper-II

Which op-amp circuit produces an output proportional to the time integral of the input?

A) Differentiator
B) Integrator
C) Comparator
D) Summing amplifier
An Op-Amp Integrator is a circuit where the output voltage is proportional to the integral of the input voltage over time. In a typical inverting integrator, a resistor is placed at the input and a capacitor is placed in the feedback loop. The output voltage is given by the formula: Vout = -(1/RC) ∫ Vin dt. Analysis of other options: - a. Differentiator: This circuit produces an output proportional to the rate of change (derivative) of the input voltage (Vout ∝ dVin/dt). - c. Comparator: This circuit compares two input voltages and outputs a high or low signal based on which input is larger; it does not perform integration. - d. Summing amplifier: This circuit produces an output that is the weighted sum of multiple input voltages.
MES Jr. Grade • 2024 • Paper-II

Which class of power amplifier conducts for more than 180° but less than 360°?

A) Class A
B) Class B
C) Class AB
D) Class C
Power amplifiers are classified based on their conduction angle (the portion of the input cycle during which the output transistor conducts current). 1. **Class A**: The transistor conducts for the full 360° of the input cycle. It provides the highest linearity but lowest efficiency. 2. **Class B**: The transistor conducts for exactly 180° (half the cycle). This is typically used in push-pull configurations to eliminate crossover distortion, though a single Class B amplifier only handles half the waveform. 3. **Class AB**: This is a hybrid between Class A and Class B. The transistor is biased such that it conducts for more than 180° but less than 360°. This is specifically designed to eliminate 'crossover distortion' found in Class B amplifiers while maintaining better efficiency than Class A. 4. **Class C**: The transistor conducts for less than 180°. These are highly efficient but produce significant distortion, making them suitable primarily for RF tuned amplifiers. Since the question asks for the class that conducts for more than 180° but less than 360°, the correct answer is Class AB.
MES Jr. Grade • 2024 • Paper-II

The gain margin of a system is defined as the factor by which gain can be multiplied before the system becomes:

A) Stable
B) Marginally stable
C) Unstable
D) Oscillatory
Gain Margin (GM) is a key stability metric in control systems, typically analyzed using the Bode plot or Nyquist plot. It is defined as the amount of additional gain that can be added to the system before it reaches the threshold of instability. 1. **Stability Threshold**: A system is considered 'marginally stable' when its closed-loop poles lie exactly on the imaginary axis of the s-plane. In the frequency domain, this occurs when the open-loop gain is exactly 1 (0 dB) at the phase crossover frequency (where the phase angle is -180°). 2. **Definition of GM**: The Gain Margin is the reciprocal of the magnitude of the open-loop transfer function at the phase crossover frequency. Mathematically, if the magnitude at -180° is |G(jωpc)|, then GM = 1 / |G(jωpc)|. 3. **Interpretation**: If you multiply the current gain by the Gain Margin, the magnitude at the phase crossover frequency becomes exactly 1. At this point, the system is no longer strictly stable but has not yet become fully unstable; it is 'marginally stable' (often characterized by sustained oscillations). Why other options are incorrect: - (a) Stable: The system is already stable if it has a positive gain margin; the GM describes how much *more* gain it can take before losing that stability. - (c) Unstable: While the system becomes unstable if the gain is increased *beyond* the gain margin, the specific point defined by the gain margin factor is the boundary, which is marginal stability. - (d) Oscillatory: While marginal stability results in oscillations, 'marginally stable' is the formal technical term used in control theory to define the stability boundary.
MES Jr. Grade • 2024 • Paper-II

What should be the nature of bandwidth for a good control system?

A) Small
B) Medium
C) Large
D) All of the mentioned
In control systems, bandwidth is defined as the range of frequencies over which the system tracks the input signal with acceptable accuracy (typically where the magnitude is within -3dB of the DC gain). 1. **Speed of Response**: There is a direct relationship between bandwidth and the rise time (speed) of a system. A larger bandwidth implies a faster response and a shorter rise time, allowing the system to respond quickly to changes in the input. 2. **Tracking Ability**: A system with a larger bandwidth can track higher-frequency input signals without significant attenuation or phase lag. 3. **Trade-off (Noise)**: While a very large bandwidth can make a system more susceptible to high-frequency noise, in the context of general 'performance' and 'speed' for a good control system, a larger bandwidth is desired to ensure agility and fast transient response. Therefore, for a system to be considered 'good' in terms of responsiveness and tracking capability, a large bandwidth is preferred.
MES Jr. Grade • 2024 • Paper-II

Define radiation pattern, beamwidth, and directivity of an antenna.

MES Jr. Grade • 2024 • Paper-II

Draw and explain the working of a square wave generator.

MES Jr. Grade • 2024 • Paper-II

How do we obtain sinusoidal output out of a class B amplifier?

A) By using non-sinusoidal inputs
B) By utilizing two transistors
C) By biasing it in the active region
D) By adding a capacitor to the output
A Class B amplifier is designed such that the transistor conducts for only one half-cycle (180 degrees) of the input sinusoidal signal. If a single transistor is used, the output is a half-wave rectified sine wave, which contains significant distortion. To obtain a full sinusoidal output, a 'Push-Pull' configuration is used. This involves utilizing two transistors: one (NPN) to amplify the positive half-cycle and another (PNP) to amplify the negative half-cycle. By combining the outputs of these two transistors, the full sinusoidal waveform is reconstructed. Analysis of other options: - Option (a): Non-sinusoidal inputs would not result in a sinusoidal output; the goal is to amplify a sine wave without distortion. - Option (c): Biasing in the active region is a general requirement for amplification, but specifically for Class B, the transistor is biased at the cutoff point (Q-point at the junction of cutoff and active), not centered in the active region (which would be Class A). - Option (d): A capacitor at the output is used for DC blocking or filtering, but it cannot reconstruct a missing half-cycle of a waveform.
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