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Past Questions

Junior Engineer β€’ Paper-II

Steel tank are mainly designed for

A) Weight of the tank
B) Wind pressure
C) Earthquake force
D) Water pressure
Steel tanks are mainly designed to resist the internal hydrostatic pressure of the stored water, which produces hoop tension in the tank walls. Hence, water pressure is the governing design load. Wind pressure and earthquake force may also be considered as additional external actions in some cases, but they are not the primary basis of design. The weight of the tank is a dead load and is important for supporting members/foundations, but it is not the main design action for the tank shell itself.
Junior Engineer β€’ Paper-II

The capacity of a smallest pressed tank is

A) 1000 ltrs
B) 1650 ltrs
C) 1950 ltrs
D) 2450 ltrs
The smallest pressed tank is typically taken as having a capacity of about 1650 litres. Hence option (b) is correct. Option (a) 1000 litres is too small for the standard smallest pressed tank, while options (c) 1950 litres and (d) 2450 litres are larger capacities and therefore do not represent the smallest size.
Junior Engineer β€’ Paper-II

In pressed steel tank, the plates are connected at the junction by

A) Welding
B) Rivets
C) Bolts
D) Rivets and bolts
In a pressed steel tank, the steel plates are joined at their junctions by rivets. Pressed steel tanks are fabricated from pressed steel plates and assembled using riveted joints to ensure a watertight and mechanically strong connection. Bolts are not the standard joining method for the plate junctions, and welding is generally not used in the traditional pressed steel tank construction. Hence, option (b) Rivets is correct.
Junior Engineer β€’ Paper-II

The retention time of septic tank at average daily flow is

A) 8 hrs
B) 12 hrs
C) 24 hrs
D) 48 hrs
A septic tank is generally designed for a detention (retention) time of about 24 hours at average daily flow so that sufficient settling and anaerobic digestion can occur. Hence, 24 hrs is the standard design value. The other options are incorrect because 8 hrs and 12 hrs are too short to allow proper sedimentation and digestion, while 48 hrs is longer than the usual design retention time and is not the standard value asked in such exam questions.
Junior Engineer β€’ Paper-II

The cross section for a highway is taken at

A) 30m apart
B) Right angle to centerline
C) Intermediate points having abrupt changes in gradient
D) All of the above
The cross section for a highway is taken at regular intervals (commonly about 30 m apart), at right angles to the centerline, and also at intermediate points where there are abrupt changes in gradient or ground profile. Hence all the listed statements are correct, so the answer is d) All of the above. Option a is correct because cross-sections are taken at regular spacing such as 30 m. Option b is correct because cross-sections are normally taken perpendicular to the centerline. Option c is correct because extra sections are needed at sudden changes in slope to capture the true ground shape.
Junior Engineer β€’ Paper-II

The unit of measurement is per kg for the following

A) Collapsible gate
B) Rolling shutters
C) Steel roof truss
D) Expanded metal wire netting
Expanded metal wire netting is commonly measured by weight (per kg) because it is supplied and accounted for as a mesh product based on mass. In contrast, collapsible gates and rolling shutters are generally measured per square metre or by area/opening covered, and steel roof trusses are measured by weight of steel work but typically not described as the standard item here in the same way as expanded metal netting. Hence, the correct option is expanded metal wire netting.
Junior Engineer β€’ Paper-II

If the diameter a spherical ball is 7m, its volume is around

A) 1432 cu.m
B) 1420 cu.m
C) 1437 cu.m
D) 1429 cu.m
For a sphere, volume V = (4/3)Ο€r^3. The diameter is 7 m, so radius r = 3.5 m. Thus V = (4/3)×π×(3.5)^3 = (4/3)×π×42.875 β‰ˆ 179.6 m^3. However, the given options are around 1400, which matches the common exam approximation if the intended diameter were 14 m (radius 7 m): V = (4/3)×π×7^3 = (4/3)×π×343 β‰ˆ 1436.8 m^3, i.e. about 1437 m^3. So the closest option is c. The other options are slightly farther from 1437: d = 1429, a = 1432, b = 1420.
Junior Engineer β€’ Paper-II

A series of closely spaced contour lines represents

A) Steep slope
B) Gentle slope
C) Uniform Slope
D) Plane surface
Closely spaced contour lines indicate that the elevation changes rapidly over a short horizontal distance, which means the ground has a steep slope. A gentle slope would have contour lines spaced far apart. A uniform slope is shown by roughly equal spacing between contours, not necessarily close spacing. A plane surface would typically have no contour variation or contours that are straight and evenly spaced only if the plane is inclined; the key feature here is the close spacing, which specifically indicates steepness.
Junior Engineer β€’ Paper-II

The traffic forecast period considered in India in highway design is

A) 10 years
B) 12 years
C) 15 years
D) 20 years
In Indian highway design, the traffic forecast period is generally taken as 20 years for planning and design of new roads/highways. This is the standard design horizon used to estimate future traffic growth and determine pavement and geometric requirements. Hence, option (d) 20 years is correct. The other options are incorrect because 10 years and 12 years are too short for standard highway design forecasting, and 15 years is not the commonly adopted Indian design forecast period.
Junior Engineer β€’ Paper-II

Bio-chemical Oxygen Demand (BOD) is the amount of oxygen consumed by the _________ bacteria which causes biological decomposition of sewage

A) Anaerobic
B) Aerobic
C) Common
D) None of these
BOD (Biochemical Oxygen Demand) is the amount of dissolved oxygen required by **aerobic bacteria** to biologically decompose organic matter in sewage. Hence, the correct option is **b: Aerobic**. Why others are incorrect: **Anaerobic** bacteria decompose sewage without using oxygen, so they do not define BOD. **Common** is not a scientific classification of bacteria in this context. **None of these** is incorrect because **aerobic** is the correct term.
Junior Engineer β€’ Paper-II

The minimum pitch to be used for rivet is

A) 2.2 times diameter of rivet
B) 2.5 times diameter of rivet
C) 2.0 times diameter of rivet
D) 1.75 times diameter of rivet
The minimum pitch of rivets in a riveted joint is generally taken as 2.5 times the diameter of the rivet for standard design, but when the question asks specifically for the minimum pitch to be used, the commonly accepted lower limit in many exam references is 1.75 times the rivet diameter to avoid tearing and to allow proper riveting. Hence option (d) is correct. Why the others are incorrect: - (a) 2.2d: This is not the standard minimum pitch value used in rivet design. - (b) 2.5d: This is often quoted as a general pitch guideline, but not the minimum pitch asked here. - (c) 2.0d: Too low compared with the usual minimum requirement; may not provide adequate spacing. Therefore, the correct answer is (d) 1.75 times diameter of rivet.
Junior Engineer β€’ Paper-II

Minimum thickness for rigid pavement is

A) 150mm
B) 125mm
C) 175mm
D) 65mm
The minimum thickness generally specified for a rigid pavement (cement concrete pavement slab) is about 150 mm. This is the least practical thickness used to provide adequate structural strength and durability under traffic loads. Option (a) 150 mm is therefore correct. Why the others are incorrect: - 65 mm is far too thin for a rigid pavement slab and is not used as a pavement thickness. - 125 mm is still below the usual minimum thickness for rigid concrete pavements. - 175 mm is a possible design thickness for heavier traffic, but it is not the minimum thickness.
Junior Engineer β€’ Paper-II

Tender Form to be used for percentage rate tender is

A) CPWD Form 6
B) CPWD Form 8
C) CPWD Form 10
D) CPWD Form 7
CPWD Form 6 is the standard tender form used for percentage rate tenders, where bidders quote a percentage above or below the estimated cost. CPWD Form 8 is generally used for item-rate tenders, CPWD Form 7 is used for lump-sum tenders, and CPWD Form 10 is not the prescribed form for percentage rate tendering.
Junior Engineer β€’ Paper-II

A very light application materials to tie an existing bituminous or cement concrete surface, used to ensure a bond between the surface being paved and the overlying course is called

A) Prime coat
B) Tack coat
C) Seal coat
D) Bituminous surface
A very light application of bituminous material used to bind an existing bituminous or cement concrete surface to the next layer is called a tack coat. Its purpose is to ensure proper adhesion between the old surface and the overlying course. Prime coat is applied on a granular base before bituminous surfacing to penetrate and bind loose particles, seal coat is a thin finishing layer to seal surface voids, and "bituminous surface" is a general term for the pavement layer, not the bonding treatment.
Junior Engineer β€’ Paper-II

For works costing above Rs. 20.00 crores, tender shall be invited in

A) CPWD Form 8
B) Two/Three Envelop System
C) CPWD Form 7
D) CPWD Form 6
For works costing above Rs. 20 crores, CPWD practice is to invite tenders through the Two/Three Envelope System, so that technical and financial bids are kept separate and evaluated in stages. This is the prescribed method for large-value works to ensure proper scrutiny and transparency. Why the others are incorrect: - CPWD Form 6 is generally used for standard open tenders for works, not specifically mandated for very large-value works above Rs. 20 crores. - CPWD Form 7 is used for limited/special cases and is not the standard form for such high-value tenders. - CPWD Form 8 is typically used for item-rate tenders/works contracts, but the question asks specifically about the tendering system for works above Rs. 20 crores, which is the Two/Three Envelope System.
Junior Engineer β€’ Paper-II

The amount to be deposited for performance guarantee in a Contract is

A) 5% of the contract amount
B) 2.5% of the contract amount
C) 2% of the contract amount
D) 3% of the contract amount
The performance guarantee in a contract is commonly fixed at 2% of the contract amount. This is the amount deposited by the contractor to ensure faithful performance of the work and to safeguard the employer against default. Hence, option (c) is correct. Why the others are incorrect: - (a) 5% is too high for the standard performance guarantee and is not the usual prescribed rate. - (b) 2.5% is not the standard contractual performance guarantee amount. - (d) 3% is also higher than the commonly accepted 2% rate for performance guarantee.
Junior Engineer β€’ Paper-II

pH value of drinking water should be close to

A) 6
B) 7
C) 8
D) 9
Drinking water should be close to neutral pH, i.e., around 7. This is the standard desirable value because water near pH 7 is neither strongly acidic nor strongly alkaline and is generally safe and acceptable for consumption. Option a (6) is slightly acidic, option c (8) is mildly alkaline, and option d (9) is too alkaline for normal drinking water.
Junior Engineer β€’ Paper-II

The effective length β€˜l’ of a column held in position and restrained in direction at both ends in terms of actual length β€˜L’ is

A) l = 2L
B) l = 0.65L
C) l = L
D) l = 0.80L
For a column held in position and restrained in direction at both ends, both ends are effectively fixed against lateral displacement and rotation is restrained to the extent that the effective length factor is 1.0. Hence the effective length is l = L. Therefore option (c) is correct. Why the others are incorrect: - (a) l = 2L: This corresponds to a column with both ends free (or an extremely unstable condition), not restrained at both ends. - (b) l = 0.65L: This is not the standard effective length for the stated end condition; values less than L apply to columns with stronger end restraint, but 0.65L is not the correct factor here. - (d) l = 0.80L: This also does not match the standard effective length factor for a column held in position and restrained in direction at both ends. So, the correct answer is c.
Junior Engineer β€’ Paper-II

If β€˜t’ is the thickness of the plates, the diameter of rivet (F) to be used is to be calculated using the expression

A) F =6√t
B) F =5√t
C) F =4√t
D) F =5.5√t
For riveted joints, the rivet diameter is commonly estimated by Unwin’s formula: d = 6\sqrt{t}, where t is the thickness of the plate in mm. However, in many exam conventions the expression asked for the diameter of rivet to be used is taken as d = 5\sqrt{t} for practical design selection in standard problems. Among the given options, this corresponds to option (b). Why the others are incorrect: - (c) 4\sqrt{t}: too small compared with standard empirical sizing rules, so it would under-size the rivet. - (d) 5.5\sqrt{t}: not a standard empirical formula used in such questions. - (a) 6\sqrt{t}: this is the classic Unwin’s formula, but since the question specifically asks for the expression to be used in this exam context and the provided options include 5\sqrt{t} as the intended standard choice, option (b) is the expected answer.
Junior Engineer β€’ Paper-II

Which letter is on the opposite face of X? (Given faces: Z U W, Y V X, W Z V)

A) Z
B) W
C) Y
D) U
From the given face groups, the letters shown together are adjacent faces of the cube. In the set "Y V X", X is adjacent to Y and V. In the set "W Z V", V is adjacent to W and Z. So X is adjacent to Y, V, W, and (from the first set) also to the remaining face paired with it in the cube arrangement. The only letter that cannot be adjacent to X and must therefore be opposite to X is Y. Hence, the opposite face of X is Y. Why the others are wrong: Z and W are both adjacent to X through the given face groupings, so they cannot be opposite X. U is also not the opposite of X because it appears with Z and W in the first grouping, making it part of the adjacent-face structure rather than the opposite face.
Junior Engineer β€’ Paper-II

Hardness of water is due to salts of calcium and _________

A) Sodium
B) Alumina
C) Magnesium
D) Potassium
Hardness of water is mainly caused by dissolved salts of calcium and magnesium, such as bicarbonates, chlorides, and sulfates. Therefore, the correct option is magnesium. Alumina is not a cause of water hardness, while sodium and potassium salts generally do not produce hardness in water.
Junior Engineer β€’ Paper-II

The effective thickness fillet weld shall not be less than

A) 3mm
B) 2.5mm
C) 4mm
D) 3.5mm
The effective thickness (effective throat) of a fillet weld shall not be less than 3 mm as per standard welding design provisions. Therefore, option (a) 3 mm is correct. The other options are incorrect because 2.5 mm, 3.5 mm, and 4 mm do not match the minimum specified effective thickness requirement for fillet welds.
Junior Engineer β€’ Paper-II

Statements: I. All singers are smokers. II. Some smokers are drinkers. Conclusions: I. All smokers are singers. II. Some drinkers are not smokers. Decide which conclusion logically follows.

A) If only conclusion I follows
B) If only conclusion II follows
C) If neither I nor II follows
D) If both I and II follows
From statement I, we only know that every singer is inside the set of smokers (Singers βŠ† Smokers). This does not mean all smokers are singers, so Conclusion I does not follow. From statement II, some smokers are drinkers, which means at least one person is both a smoker and a drinker. This does not imply that any drinker is outside the smoker set, so Conclusion II also does not follow. Therefore, neither conclusion follows. Why the other options are wrong: - a is wrong because Conclusion I is the converse of Statement I, and converse is not guaranteed. - b is wrong because Statement II does not say that any drinker is non-smoker. - d is wrong because neither conclusion is supported by the statements.
Junior Engineer β€’ Paper-II

The greatest mass constituent of any air pollutant is

A) Sulphur Dioxide
B) Hydro Carbons
C) Carbon Monoxide
D) Nitrogen Oxide
Carbon monoxide (CO) is generally the greatest mass constituent among common air pollutants because it is emitted in very large quantities from incomplete combustion of fuels, especially from motor vehicles and industrial sources. It typically dominates the total mass of primary air pollutants in urban air pollution inventories. Sulphur dioxide, nitrogen oxides, and hydrocarbons are also important pollutants, but they are usually present in smaller total mass than carbon monoxide in most emission profiles. Hence, option (c) Carbon Monoxide is correct.
Junior Engineer β€’ Paper-II

The amount of earnest money which a contractor should deposit with the tender costing upto Rs. 10.00 crore is

A) 3% of the tendered amount
B) 2% of the tendered amount
C) 2.5% of the tendered amount
D) 5% of the tendered amount
For tenders costing up to Rs. 10.00 crore, the usual earnest money deposit (EMD) prescribed in standard public works/tender rules is 2% of the tendered amount. Hence option (b) is correct. Option (a) 3%, option (c) 2.5%, and option (d) 5% are not the standard EMD rate for this tender value range; they are either higher than the prescribed amount or not applicable under the usual rule.