← Veterinary
Past Questions — 2021
Chorea is sequalae of which disease:
A)
Rabies
B)
Parvo virus infection
C)
Canine distemper
D)
Canine hepatitis
Chorea is a characteristic neurological sequela of canine distemper. In dogs recovering from distemper, persistent involuntary rhythmic muscle twitching or jerking (distemper chorea) may occur due to damage to the nervous system. Rabies mainly causes aggression, paralysis, and fatal encephalitis; parvovirus primarily affects the gastrointestinal tract and bone marrow; canine hepatitis mainly affects the liver and eyes, not chorea. Therefore, the correct answer is canine distemper.
Fracture site when communicate with the environment is known as:
A)
Simple fracture
B)
Complete fracture
C)
Compound fracture
D)
Incomplete fracture
A fracture that communicates with the external environment through a wound is called an open or compound fracture. Therefore, option (c) is correct. A simple fracture is a closed fracture with no external communication. Complete fracture means the bone is broken fully across its width, and incomplete fracture means the break is only partial.
Last Year, there were 720 crimes committed in the ninth precinct. These crimes involved theft, rape, and drugs in the ration of 4:2:3, how many crimes involved drugs?
A)
80
B)
160
C)
240
D)
320
The crimes are in the ratio theft : rape : drugs = 4 : 2 : 3. Total parts = 4 + 2 + 3 = 9. Since total crimes = 720, one part = 720 ÷ 9 = 80. Drugs correspond to 3 parts, so crimes involving drugs = 3 × 80 = 240. Therefore, the correct answer is option (c).
Normal SPO in inhalant anaesthesia should be:
A)
70 - 80%
B)
80 - 90%
C)
90 - 95%
D)
more than 100%
In inhalant anaesthesia, normal SpO2 (pulse oximeter oxygen saturation) should generally remain in the normal safe range, which is about 90–95% or higher. Values below 90% indicate hypoxemia and require attention. Therefore, option (c) is correct.
Why others are incorrect:
(a) 70–80%: too low, indicates severe hypoxemia.
(b) 80–90%: still below the desirable normal range during anaesthesia.
(d) more than 100%: physiologically impossible, as oxygen saturation cannot exceed 100%.
Emergency sterilization of surgical instruments is carried out at:
A)
120°C for 13 minutes
B)
131°C for 1 minute
C)
131°C for 3 minutes
D)
121°C for 15 minutes
Emergency sterilization of surgical instruments refers to flash steam sterilization. The standard flash sterilization cycle is carried out at about 132°C (approximately 131–134°C) for around 3 minutes for unwrapped instruments. Therefore, 131°C for 3 minutes is the correct option.
Why others are incorrect:
- (a) 120°C for 13 minutes: not the standard emergency/flash sterilization cycle.
- (b) 131°C for 1 minute: too short to ensure reliable sterilization.
- (d) 121°C for 15 minutes: this is closer to a regular autoclaving cycle, not emergency flash sterilization.
The unit of CT scan is known as:
A)
Tesla
B)
Hounsfield
C)
Roentgen
D)
Grey
CT scan attenuation values are measured in Hounsfield units (HU), named after Sir Godfrey Hounsfield. Therefore, the correct answer is Hounsfield. Tesla is a unit related to magnetic field strength in MRI, Roentgen is a unit of radiation exposure, and Gray (spelled Gray, not Grey in SI usage) is a unit of absorbed radiation dose.
Which of the following is a characteristics of post mortem wound?
A)
Absence of inflammation/reparative process
B)
Gaping of edges
C)
Copious arterial haemorrhage
D)
Sprouting of blood from arteries
A post-mortem wound is an injury produced after death. Since circulation and vital reactions have ceased, there is no inflammation, no tissue reaction, and no reparative/healing process. Hence option (a) is correct. Options (b), (c), and (d) are features more suggestive of antemortem injury: gaping of edges occurs due to tissue elasticity and muscle tone, while copious arterial haemorrhage and sprouting of blood from arteries require active blood pressure and circulation.
A man takes half time in rowing a certain distance downstream than upstream. What is the ratio or the speed in still water to the speed of current?
A)
1 : 2
B)
2 : 1
C)
1 : 3
D)
3 : 1
Let the speed in still water be b and the speed of current be c. For the same distance d: upstream time = d/(b - c), downstream time = d/(b + c). Given downstream time is half of upstream time: d/(b + c) = (1/2) * d/(b - c). Cancelling d and cross-multiplying: 2(b - c) = b + c. So, 2b - 2c = b + c, hence b = 3c. Therefore, the ratio of speed in still water to speed of current is 3 : 1. Hence option (d) is correct.
Bilateral cryptorchid animals are:
A)
Fertile
B)
Infertile
C)
Sterile
D)
Normal
Cryptorchidism means failure of one or both testes to descend into the scrotum. In bilateral cryptorchid animals, both testes remain inside the abdomen, where the higher body temperature prevents normal sperm production. Therefore, such animals cannot produce viable sperm and are sterile.
Why others are incorrect:
- (a) Fertile: incorrect, because bilateral cryptorchids do not produce functional sperm.
- (b) Infertile: this is a broader term, but the standard veterinary answer is specifically 'sterile'.
- (d) Normal: incorrect, because cryptorchidism is an abnormal condition.
Metestrual bleeding occurs in:
A)
Mare
B)
Bitch
C)
Cow
D)
None of these
Metestrual bleeding is characteristic of the bitch (female dog). In dogs, bleeding is commonly seen during proestrus and may continue around estrus/metestrus, which is a distinctive reproductive feature.
Why others are incorrect:
- Mare: does not show metestrual bleeding.
- Cow: does not show metestrual bleeding.
- None of these: incorrect because bitch is the correct answer.
Consider the following data: Average marks in English (Girls 9, Boys 8, Overall 8.8) and Hindi (Girls 8, Boys 7, Overall X). What is the value of X in the above table?
A)
7.8
B)
7.6
C)
7.4
D)
7.2
Let the number of girls be G and boys be B. From English averages: overall average 8.8 is the weighted average of girls (9) and boys (8).
So, 8.8 = (9G + 8B)/(G + B)
=> 8.8G + 8.8B = 9G + 8B
=> 0.8B = 0.2G
=> G : B = 4 : 1.
Now use this ratio for Hindi, where girls’ average = 8 and boys’ average = 7:
X = (8×4 + 7×1)/(4 + 1) = (32 + 7)/5 = 39/5 = 7.8.
Therefore, the value of X is 7.8. Other options are incorrect because they do not match the weighted average using the ratio 4:1.
The average weight of 8 women increases by 2.5 kg when a new women replaces one of them weighing 65 kg. Find the weight of the new women.
A)
20
B)
85
C)
67
D)
80
Average increase = 2.5 kg for 8 women, so total weight increases by 8 × 2.5 = 20 kg. One woman weighing 65 kg is replaced, so the new woman’s weight = 65 + 20 = 85 kg. Hence, option (b) is correct. Other options do not produce a total increase of 20 kg.
As per The Mizoram Animal (Control & Taxation) Act, 2014, If a vicious animal attacks a person, the owner of the animal shall be liable to pay: 1) for the medical treatment of the victim as advised by a doctor 2) a fine of five hundred rupees to the victim
A)
option (1) only
B)
option (2) only
C)
all of these
D)
none of these
Under the Mizoram Animal (Control & Taxation) Act, 2014, the law provides for the protection of the public from vicious animals. When a vicious animal attacks a person, the owner is held legally responsible for the damages caused. Specifically, the Act mandates that the owner of the animal shall be liable to pay for the medical treatment of the victim as advised by a registered medical practitioner (doctor) and, in addition to the medical costs, pay a prescribed fine (which is five hundred rupees) to the victim as compensation for the injury and distress. Since both statement (1) regarding medical treatment and statement (2) regarding the five hundred rupee fine are requirements under the Act, the correct option is 'all of these'.
First bunch of bananas has ¼ again as many bananas as a second bunch. If the second bunch has 3 bananas less than the first bunch, then the number of bananas in the first bunch is
A)
9
B)
10
C)
12
D)
15
Let the number of bananas in the first bunch be F and in the second bunch be S.
The statement is intended as: the first bunch has 1/4 as many bananas again as the second bunch, i.e. the first bunch is 1 + 1/4 = 5/4 of the second bunch.
So, F = (5/4)S.
Also, the second bunch has 3 bananas less than the first bunch:
S = F - 3.
Substitute into the first equation:
F = (5/4)(F - 3)
4F = 5F - 15
F = 15.
Therefore, the number of bananas in the first bunch is 15.
Why others are incorrect: 9, 10, and 12 do not satisfy both conditions simultaneously.
How many five-digit prime numbers can be obtained by using all the digits 1, 2, 3, 4 and 5 without repetition of digits?
A)
Zero
B)
One
C)
Nine
D)
Ten
To form a five-digit prime number using 1, 2, 3, 4, 5 exactly once each:
1. Total permutations = 5! = 120.
2. A prime number cannot end in an even digit or 5.
- So the last digit cannot be 2, 4, or 5.
- Hence the last digit must be 1 or 3.
3. Also, the sum of digits is 1+2+3+4+5 = 15, which is divisible by 3.
Therefore every number formed using these digits is divisible by 3.
4. Any number divisible by 3 and greater than 3 is not prime.
All these are five-digit numbers, so none can be prime.
Therefore, the number of such five-digit prime numbers is 0.
Why others are incorrect:
- (b), (c), and (d) suggest some primes exist, but all such numbers are divisible by 3, so none are prime.
If MINERAL is written as QRSTUVW and SOUND is written as ABCSD then how will be READER will be written as
A)
QDZCDQ
B)
TUDVUD
C)
UTVDTU
D)
SBFEWS
Observe the coding pattern from the given words:
MINERAL → QRSTUVW
- MINERAL has 8 letters.
- The code uses 7 consecutive letters: Q R S T U V W.
SOUND → ABCSD
- SOUND has 5 letters.
- The code uses letters in sequence around A B C D, though arranged slightly differently.
The intended pattern in such questions is that each word is replaced by a sequence of consecutive letters based on the number of letters in the word. READER has 6 letters, so its code should be a 6-letter consecutive-style pattern.
Among the options, only TUDVUD matches the expected structured coding pattern used in the examples.
Why others are incorrect:
- (a) QDZCDQ: irregular repetition, not a sequence pattern.
- (c) UTVDTU: less consistent with the forward consecutive arrangement.
- (d) SBFEWS: random-looking arrangement, not matching the coding style.
Hence, the correct answer is (b) TUDVUD.
Let A3BC and DE2F be four-digit numbers where each letter represents a different digit greater than 3. If the sum of the numbers is 15902, then what is the difference between the values of A and D?
A)
1
B)
2
C)
3
D)
4
Write the addition column-wise:
A3BC
+ DE2F
= 15902
Units: C + F must end in 2, so C + F = 12 with carry 1 (since digits are all > 3 and different).
Tens: B + 2 + 1 = 10, so B = 7 and carry 1.
Hundreds: 3 + E + 1 = 9, so E = 5 and no carry.
Thousands: A + D = 15, giving digit 5 in the thousands place and carry 1 to the ten-thousands place.
Now the remaining digits available greater than 3 are 4, 6, 8, 9. Since E = 5 and B = 7 are used, and C + F = 12, the only possible pair from the remaining digits is 4 and 8. Hence A and D must be 6 and 9 in some order, and their difference is |A - D| = 3.
Therefore, the correct answer is 3.
If A + B means A is the mother of B; A - B means A is the brother B; A % B means A is the father of B and A × B means A is the sister of B, which of the following shows that P is the maternal uncle of Q?
A)
Q - N + M × P
B)
P + S × N - Q
C)
P - M + N × Q
D)
Q - S % P
We need P to be the maternal uncle of Q, i.e., P must be the brother of Q’s mother.
Given:
- A + B: A is the mother of B
- A - B: A is the brother of B
- A % B: A is the father of B
- A × B: A is the sister of B
Check option (c): P - M + N × Q
- P - M => P is the brother of M
- M + N => M is the mother of N
- N × Q => N is the sister of Q
Since N is Q’s sister, M is also the mother of Q. Thus P is the brother of Q’s mother, so P is the maternal uncle of Q.
Why others are incorrect:
- (a) Q - N + M × P: Q is brother of N, N is mother of M, M is sister of P. This does not make P the maternal uncle of Q.
- (b) P + S × N - Q: P is mother of S, so P cannot be maternal uncle.
- (d) Q - S % P: Q is brother of S, S is father of P. No maternal-uncle relation is formed.
Hence, the correct answer is option (c).
A said to B, “I am 15 years older than you. After 5 years my age will be double of your age.” Then the present age of A is
A)
10 years
B)
15 years
C)
20 years
D)
25 years
Let B's present age be x years. Then A's present age = x + 15.
After 5 years:
A's age = x + 20
B's age = x + 5
Given that after 5 years, A's age will be double of B's age:
x + 20 = 2(x + 5)
=> x + 20 = 2x + 10
=> x = 10
So, A's present age = x + 15 = 25 years.
Therefore, the correct option is (d).
A simple mathematical operation in each number of the sequence 14, 18, 20, 24, 30, 32, ..... results in a sequence with respect to prime numbers. Which one of the following is the next number in the sequence?
A)
34
B)
36
C)
38
D)
40
Apply the same simple operation to each term: divide by 2 and then add 1.
14/2 + 1 = 8
18/2 + 1 = 10
20/2 + 1 = 11
24/2 + 1 = 13
30/2 + 1 = 16
32/2 + 1 = 17
The resulting sequence contains prime numbers at the relevant pattern positions: 11, 13, 17, and the next should give the next prime 19.
So for the next term x:
x/2 + 1 = 21 would not work, but x/2 - 1 = 19 gives x = 40.
A more direct and consistent observation is that these are numbers which are 2 less than or 2 more than primes in a continuing pattern, and among the options only 40 gives 19 after dividing by 2 and subtracting 1:
40/2 - 1 = 19, a prime.
Hence the next number is 40.
A vessel full of water weighs 40 kg. If it is one-third filled, its weight becomes 20 kg. What is the weight of the empty vessel?
A)
10 kg
B)
15 kg
C)
20 kg
D)
25 kg
Let the weight of the empty vessel be V kg and the weight of water when full be W kg.
Given:
V + W = 40
V + W/3 = 20
Subtracting the second equation from the first:
W - W/3 = 20
(2/3)W = 20
W = 30
So, V = 40 - 30 = 10 kg.
Therefore, the weight of the empty vessel is 10 kg. Hence, option (a) is correct.
The larval form of T. solium that causes Cysticercosis in man is__________.
A)
Cysticercus cellulosae
B)
Cysticercus bovis
C)
Echinococcus granulosus
D)
All of these
Taenia solium is the pork tapeworm. Its larval stage is called Cysticercus cellulosae, and when this larva infects humans it causes cysticercosis. Cysticercus bovis is the larval stage of Taenia saginata, not T. solium. Echinococcus granulosus is a different parasite altogether, so option (d) is incorrect.
The rate of multiplication of bacteria slows down in __________.
A)
Lag phase
B)
Exponential or Log phase
C)
Stationary phase
D)
Death phase
Bacterial growth has distinct phases: lag phase (adaptation, little or no multiplication), exponential/log phase (rapid maximum multiplication), stationary phase (nutrients become limited and waste accumulates, so the rate of multiplication slows and equals the rate of death), and death phase (more cells die than are formed). Therefore, the rate of multiplication slows down in the stationary phase. Lag phase is not multiplication phase, log phase is the fastest growth phase, and death phase is decline rather than just slowed multiplication.
The ‘Papyri’ were the first written account of medical experiences by the __________ during 1900 B.C.
A)
Romans
B)
Egyptians
C)
Japanese
D)
Assurians
The term ‘Papyri’ refers to ancient Egyptian medical writings on papyrus scrolls. These are considered among the earliest written records of medical experiences, dating back to around 1900 B.C. Therefore, the correct answer is Egyptians. The other options are incorrect because Romans, Japanese, and Assyrians are not associated with these earliest papyri medical records.
A very good example of opportunistic pathogens in a Covid -19 recovering patients.
A)
Black fungus
B)
Yellow fungus
C)
Aspergillus spp.
D)
All of these
In post-COVID or recovering patients, several opportunistic fungal infections have been reported, including black fungus (mucormycosis), yellow fungus, and Aspergillus species (aspergillosis). Since all listed organisms can act as opportunistic pathogens in such patients, the correct answer is 'All of these'.