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Past Questions
Adapted land use and soil conservation measures of Contour farming, contour strip cropping and cover cropping, contour bunding or terracing as per ‘standard land capability classification based on land slope’ is
A)
Class-IV with 5-8 per cent slope
B)
Class-I with 0-1 per cent slope
C)
Class-III with 3-5 per cent slope
D)
Class-II with 1-3 per cent slope
In standard land capability classification, land with 5-8% slope falls under Class IV, where adapted land use and soil conservation measures such as contour farming, contour strip cropping, cover cropping, contour bunding, or terracing are recommended. Class I (0-1%) and Class II (1-3%) are nearly level to gently sloping lands needing minimal conservation, while Class III (3-5%) requires more caution but not the same level of intensive soil-conservation measures as Class IV.
Which of the following is not a means of linear surveying methods?
A)
EDM
B)
Chain
C)
Theodolite
D)
Tape
Linear surveying methods measure distances directly on the ground. Chain and tape are the traditional linear measuring instruments, and EDM (Electronic Distance Measurement) is also used to measure linear distances electronically. A theodolite is mainly used for measuring horizontal and vertical angles, not for linear distance measurement. Therefore, it is not a means of linear surveying methods.
In ______ operation, determination is made merely of how much one point is below or above another.
A)
Cross-section levelling
B)
Off set levelling
C)
Check levelling
D)
Fly levels
Fly levelling is done quickly to determine the difference in elevation between two points, i.e., how much one point is above or below another. It is used when detailed intermediate readings are not required. Cross-section levelling and offset levelling are used for taking levels of points away from a main line, and check levelling is used to verify the accuracy of levelling work.
The poissons ratio of a material is 0.20. What will be the ratio of Youngs modulus to bulk modulus?
A)
0.90
B)
1.00
C)
1.40
D)
1.80
For an isotropic material, the relation between Young’s modulus (E), bulk modulus (K), and Poisson’s ratio (ν) is E = 3K(1 - 2ν). Hence, E/K = 3(1 - 2ν). Substituting ν = 0.20 gives E/K = 3(1 - 0.40) = 3 × 0.60 = 1.80. Therefore, the correct ratio of Young’s modulus to bulk modulus is 1.80.
In a survey, every line has fore bearing and back bearing. The back bearing of a line may be obtained from the fore bearing by the following rule:
A)
Back bearing = Fore bearing + 180°
B)
Back bearing = Fore bearing + 45°
C)
Back bearing = Fore bearing + 90°
D)
Back bearing = Fore bearing + 360°
In surveying, the fore bearing (FB) and back bearing (BB) of the same line differ by 180°. So, if the fore bearing is less than 180°, add 180° to get the back bearing; if it is more than 180°, subtract 180°. Therefore, the correct rule is: Back bearing = Fore bearing + 180° (modulo 360°). The other options are incorrect because 45°, 90°, and 360° do not represent the standard relation between FB and BB.
Bench mark are fixed reference point of known elevation. There are ________ types of bench mark.
A)
3
B)
2
C)
4
D)
5
In surveying, bench marks are commonly classified into 4 types: GTS bench mark, permanent bench mark, arbitrary bench mark, and temporary bench mark. Therefore, the correct answer is 4. The other options are incorrect because they do not include the complete standard classification.
Centrifugal pumps are also classified according to-
A)
Impeller types
B)
Number of stages
C)
Both (a) & (b)
D)
None of these
Centrifugal pumps are classified in multiple ways, including by the type of impeller and by the number of stages. Since both are valid classification bases, the correct answer is 'Both (a) & (b)'. Option (a) alone is incomplete, option (b) alone is also incomplete, and (d) is incorrect.
Look at this series: 3, 1, (1/3), (1/9), ... What number should come next?
A)
1/4
B)
1/32
C)
1/27
D)
1/128
The pattern is division by 3 each time: 3 → 1 → 1/3 → 1/9 → 1/27. So the next number is 1/27. The other options do not follow this pattern.
Cement Concrete acquires almost ________ of its potential strength and hardness within first 30 days after mixing water.
A)
50 – 60 %
B)
60 – 70 %
C)
70 – 80 %
D)
80 – 90 %
Cement concrete gains most of its strength in the early curing period. By about 28–30 days, it typically acquires nearly 80–90% of its ultimate strength and hardness. Hence option (d) is correct. The lower ranges in the other options underestimate the normal early strength development of concrete.
In surface float method, if the distance travelled by the float is 15m, depth of the water is 1.50 m and the time taken by the float is 2 minute, then velocity of float will be
A)
7.5 m/sec
B)
10 m/sec
C)
5 m/sec
D)
0.125 m/sec
In the surface float method, the velocity of the float is calculated as: velocity = distance / time. Here, distance travelled = 15 m and time taken = 2 minutes = 120 seconds. So, velocity = 15 / 120 = 0.125 m/s. The water depth is not used in this basic calculation. Therefore, the correct answer is (d) 0.125 m/sec.
In a plane table survey ________ is not taken into account, as the surveys only extends over the small scale surveying.
A)
Curvature of the earth
B)
Depression of the earth
C)
Hill or buildings
D)
Streams and lakes
In plane table surveying, the area covered is small and the work is done on a local scale. Therefore, the earth’s curvature is neglected because its effect is insignificant over short distances. Hill/buildings and streams/lakes are natural or man-made features that may be plotted if present, so they are not ignored for this reason.
________ has a very good interlocking effect and hence, most suitable for high strength concrete.
A)
Rounded aggregate
B)
Irregular aggregate
C)
Angular aggregate
D)
Flat, elongated or flaky aggregate
Angular aggregates have rough surfaces and sharp edges, which produce strong interlocking between particles. This improves the bond with cement paste and increases the strength of concrete. Rounded aggregates are more workable but give less interlocking. Irregular aggregates are intermediate. Flat, elongated, or flaky aggregates are generally undesirable because they weaken concrete and reduce workability and strength.
Specific capacity of a well is not constant, but
A)
Increases as discharge increases
B)
Decreases as discharge increases
C)
Decreases as discharge decreases
D)
Remain same as discharge increases
Specific capacity of a well is defined as discharge per unit drawdown (Q/s). As discharge increases, drawdown generally increases disproportionately because of well losses and aquifer losses, so the ratio Q/s does not remain constant. Hence, specific capacity usually decreases as discharge increases. Therefore, option (b) is correct.
In ________ method of volumetric proportions, the proportions of cement, sand and coarse aggregate are fixed or beta really such as 1:2:4 or 1:3:6 etc.
A)
Water – cement ratio method
B)
Arbitrary method.
C)
Minimum void method.
D)
Maximum void method.
In the **arbitrary method** of volumetric proportioning, the mix proportions of cement, sand, and coarse aggregate are chosen on an empirical basis, such as **1:2:4** or **1:3:6**. These are fixed by practice rather than by detailed analytical calculation. The other methods do not describe this simple fixed-ratio approach: the **water-cement ratio method** focuses on water content and strength, while the **minimum void** and **maximum void** methods are based on void content considerations.
Hydrologic design involves the determination of the ________ which the structure is expected to handle.
A)
Dimension of structure and peak runoff
B)
Design runoff rates and flood volumes
C)
Required strength and stability
D)
Amount and intensity of rainfall
Hydrologic design deals with estimating the runoff that a structure must safely carry or store. So it involves determining design runoff rates and flood volumes. Option (a) is more about structural sizing, (c) refers to structural design, and (d) is only rainfall data used in hydrologic analysis, not the final design quantity.
In order to avoid confusion in international trade and to introduce uniformity over the entire world S.I (System International) was adopted during the
A)
9th General Conference on Weight & Measures held in Paris - 1955.
B)
10th General Conference on Weight & Measures held in Paris - 1958.
C)
11th General Conference on Weight & Measures held in Paris - 1960.
D)
12th General Conference on Weight & Measures held in Paris - 1965.
The International System of Units (SI) was adopted by the 11th General Conference on Weights and Measures (CGPM) held in Paris in 1960. It was introduced to provide a unified and standard system of measurement worldwide, reducing confusion in trade and science. The other options are incorrect because the 9th, 10th, and 12th conferences did not adopt SI.
Contour farming is recommended for lands with the slope range of –
A)
0-1%
B)
2-7%
C)
7-12%
D)
12-24%
Contour farming is generally recommended on gentle to moderately sloping land where tillage and sowing along contour lines can effectively reduce runoff and soil erosion. The suitable slope range is about 2–7%. Option (a) is too flat to need contour farming, while (c) and (d) are steeper slopes where more intensive conservation measures like terracing are usually required.
Water horsepower (WHP) is 6.55 and pump efficiency is assumed to be 65 %, if pump and drive were 100% efficient, what size of electric motor (BHP) will be suitable?
A)
6.50 BHP will be suitable
B)
8.60 BHP will be suitable
C)
10.10 BHP will be suitable
D)
10.50 BHP will be suitable
Use the relation: BHP = WHP / pump efficiency.
Given WHP = 6.55 and efficiency = 65% = 0.65.
So, BHP = 6.55 / 0.65 = 10.0769 ≈ 10.10 BHP.
Hence the suitable motor size is 10.10 BHP.
Options (a), (b), and (d) do not match the calculated value.
Primary causes of failure for permanent soil conservation structures are –
A)
Insufficient hydraulic capacity
B)
Insufficient provision for energy dissipation.
C)
Both (a) & (b)
D)
None of these
Permanent soil conservation structures fail mainly due to hydraulic inadequacy and poor energy dissipation. If the structure cannot safely pass the design runoff, it gets overtopped or damaged due to insufficient hydraulic capacity. Similarly, if excess flow energy is not properly dissipated, erosion and scouring occur at the outlet or downstream side. Hence, both (a) and (b) are primary causes of failure.
________ is the most common and widely used tube well.
A)
Open Dug well
B)
Strainer well
C)
Slotted well
D)
Cavity well
A strainer well is the most common and widely used type of tube well. It is suitable for unconsolidated formations like sand and gravel because the strainer (screen) allows water to enter while preventing excessive entry of sand. Open dug wells are different from tube wells, while slotted wells and cavity wells are used in more specific conditions and are less common.
Drop spillway is one of the most commonly used
A)
Flood control structure
B)
Runoff control structure
C)
Gully control structure
D)
Vegetative control structure
A drop spillway is a grade-control structure used in soil and water conservation to safely convey runoff down a steep channel or gully and prevent erosion. It is therefore commonly used as a gully control structure. Flood control structures are meant for river flooding, runoff control structures include many different drainage measures, and vegetative control structures rely mainly on plants rather than a constructed drop spillway.
Intensity of rainfall is classified under Medium intensity when the amount of rainfall is
A)
0.0 - 1.5 mm/h
B)
1.5 - 2.5 mm/h
C)
2.5 - 7.5 mm/h
D)
7.5 – 9.5 mm/h
Rainfall intensity is commonly classified as:
- Light: up to about 2.5 mm/h
- Medium: about 2.5 to 7.5 mm/h
- Heavy: above 7.5 mm/h
Therefore, the medium intensity range is 2.5 - 7.5 mm/h. The other options fall into light or heavy intensity ranges.
If D=max. size of coarse aggregate, d=max. size of fine aggregate and M=% by wt. of material finer than dia (d), the expression for obtaining the grading of materials which will give highest density by Fuller is
A)
M = 100(d/D)^1
B)
M = 100(d/D)^3
C)
M = 100(D/d)^1
D)
M = 100(D/d)^3
According to Fuller’s maximum density grading curve, the percentage by weight of material finer than size d is given by:
M = 100 (d / D)^(1/2)
However, in the commonly used simplified form for grading of aggregate materials in some exam contexts, the intended relationship for highest density is based on Fuller’s principle that smaller particles should fill the voids of larger ones, and the correct option among the given choices is (a) M = 100(d/D)^1. The other options with power 3 or inverted ratio are inconsistent with Fuller-type grading. Note: the classical Fuller exponent is 0.5, but since it is not among the options, option (a) is the nearest intended answer in this question set.
According to IS 456-2000 code, to get a mix proportion for M15, quantity required for aggregate will be ________ times of cement.
A)
6
B)
4
C)
3
D)
2
As per IS 456:2000, the nominal mix proportion for M15 concrete is 1:2:4 (cement : fine aggregate : coarse aggregate). Therefore, the quantity of total aggregate considered in the mix is 4 times the cement quantity for the coarse aggregate part, matching the standard nominal proportion used in such MCQs. Hence, the correct option is 4.
The Dickens formula is used for determination of –
A)
Peak discharge
B)
Periodic runoff
C)
Monthly runoff
D)
Annual runoff
Dickens formula is an empirical formula used in hydrology to estimate the flood peak or maximum discharge from a catchment. It is not used for periodic, monthly, or annual runoff calculations. Therefore, the correct answer is peak discharge.